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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
4 men or 6 women or 10 children can paint a house in 5 days. The painting is given to a couple and their 5 sons. They finish the job in
Correct
Answer : b
4 men 6 women = 10 children
1 man = (5/2)children
1 women = (5/3) children
Now, 1 couple + 5 children
=1 man + 1 woman + 5 children
= [(5/2)+(5/3)+5]=(55/6) children
According to the formula,
M1 D1 = M2 D2
10 * 5 = (55/6)*D2
∴D2 = (60/11)=5(5/11)days
Incorrect
Answer : b
4 men 6 women = 10 children
1 man = (5/2)children
1 women = (5/3) children
Now, 1 couple + 5 children
=1 man + 1 woman + 5 children
= [(5/2)+(5/3)+5]=(55/6) children
According to the formula,
M1 D1 = M2 D2
10 * 5 = (55/6)*D2
∴D2 = (60/11)=5(5/11)days
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Question 2 of 5
2. Question
If 5 boys take 7 h to pack 35 toys, how many boys can pack 65 toys in 3 h?
Correct
Answer: e
Given, M1 = 5, M2 = ?, T1 = 7, T2 = 3
W1 = 35 and W2 = 65
According to the formula,
M1T1W2 = M2T2W1 [by Technique 1]
5 * 7 * 65 = m2 * 3 * 35
∴M2 = [(5 * 7 * 65)/(35 * 3)] = (65/3) boys
Incorrect
Answer: e
Given, M1 = 5, M2 = ?, T1 = 7, T2 = 3
W1 = 35 and W2 = 65
According to the formula,
M1T1W2 = M2T2W1 [by Technique 1]
5 * 7 * 65 = m2 * 3 * 35
∴M2 = [(5 * 7 * 65)/(35 * 3)] = (65/3) boys
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Question 3 of 5
3. Question
A and B can complete a work in 8 days, working together. B alone can do it in 12 days. After working for 4 days, B left the work. How many days will A take to complete the remaining work?
Correct
Answer: a
(A+B)’s 1 day’s work = (1/8)
B’s 1 day’s work = (1/12)
∴A’s 1 day’s work = (1/8)-(1/12)=[(3-2)/24]=(1/24)
∴A can complete the work in 24 days.
Now, B’s 4 day’s work = (4/12) = 1/3)
Remaining work =1 – (1/3) = (2/3)
As, time taken by A to complete the work is 24 days
∴Time taken by A to do (2/3) of the work= (2/3)* 24 = 16 days
Incorrect
Answer: a
(A+B)’s 1 day’s work = (1/8)
B’s 1 day’s work = (1/12)
∴A’s 1 day’s work = (1/8)-(1/12)=[(3-2)/24]=(1/24)
∴A can complete the work in 24 days.
Now, B’s 4 day’s work = (4/12) = 1/3)
Remaining work =1 – (1/3) = (2/3)
As, time taken by A to complete the work is 24 days
∴Time taken by A to do (2/3) of the work= (2/3)* 24 = 16 days
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Question 4 of 5
4. Question
In how many ways, can the letters of the word ‘ASSASSINATION be arranged, so that all the S are together?
Correct
Answer : c
When All S are taken together, then AS5ASS5INATION are letters.
So, 10 letters in total Can be arranged in 10! ways.
[because All ‘S are considered as 1]
But, here are 3 A’ and 2 T and 2 ‘N’.
Required number of ways = (10!)/(3! *2!* 2!) = 151200
Incorrect
Answer : c
When All S are taken together, then AS5ASS5INATION are letters.
So, 10 letters in total Can be arranged in 10! ways.
[because All ‘S are considered as 1]
But, here are 3 A’ and 2 T and 2 ‘N’.
Required number of ways = (10!)/(3! *2!* 2!) = 151200
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Question 5 of 5
5. Question
In many different signals, can be made by 5 flags from 8 flags of different colours?
Correct
Answer : d
The number of ways taking 5 flags out of 8 flags = 8!/(8-5)! = 8!/3!
= (8* 7 *6 *5 *4 *3!)/3! = 6720
Incorrect
Answer : d
The number of ways taking 5 flags out of 8 flags = 8!/(8-5)! = 8!/3!
= (8* 7 *6 *5 *4 *3!)/3! = 6720
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