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Question 1 of 5
1. Question
In a city, 12% of households earn less than Rs 30000 per year, 6% households earn more than Rs 200000 per year, 22% households earn more than Rs. 100000 per year and 990 households earn between Rs 30000 and Rs 100000 per year. How many households earn between Rs 100000 and Rs 200000 per year?
Correct
Ans : b
According to the questi0on,
6% of households income > Rs. 200000.
22% of households income > Rs. 100000.
Therefore, (22-6) = 16% of households income is between Rs. 1000000 to 2000000.
So, 12% + 16% +990+16%+6% = 100%
990=(100-34)%
990=66%
Hence, 16% = (990/66)´16
=240
So, 240 households earn between Rs 100000 and Rs 200000.
Incorrect
Ans : b
According to the questi0on,
6% of households income > Rs. 200000.
22% of households income > Rs. 100000.
Therefore, (22-6) = 16% of households income is between Rs. 1000000 to 2000000.
So, 12% + 16% +990+16%+6% = 100%
990=(100-34)%
990=66%
Hence, 16% = (990/66)´16
=240
So, 240 households earn between Rs 100000 and Rs 200000.
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Question 2 of 5
2. Question
There is a milk sample with 50% water in it. If 1/3rd of this milk is added to equal amount of püre milk, then water in the new mixture will fall down to
Correct
Ans: a
Suppose in 1 L of milk sample, 50% [or ½ part]
Is water and 50% [or ½ part] is milk.
According to the question,
1/3L of mixture + 1/3 L of pure milk = 2/3 L of new sample.
So, water in new sample = 1/3 * 1/2 = 1/6 L
Therefore, percentage of water in new sample =[( 1/6L)/(2/3L)]*100 = 25%
Hence, water in the new sample will fall down from 50% to 25%.
Incorrect
Ans: a
Suppose in 1 L of milk sample, 50% [or ½ part]
Is water and 50% [or ½ part] is milk.
According to the question,
1/3L of mixture + 1/3 L of pure milk = 2/3 L of new sample.
So, water in new sample = 1/3 * 1/2 = 1/6 L
Therefore, percentage of water in new sample =[( 1/6L)/(2/3L)]*100 = 25%
Hence, water in the new sample will fall down from 50% to 25%.
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Question 3 of 5
3. Question
A freight train left Delhi for Mumbai at an average speed of 40 km/hr. Two hours later, an express train left Delhi for Mumbai, following the freight train on a parallel track at an average speed of 60 km/hr. How far from Delhi would the express train meet the freight train?
Correct
Ans: c
Let the distance covered by freight and express trains be ‘x’ km in time ‘t’ hr and ‘t – 2’ hr, respectively.
According to the question,
40* t 60x (t – 2)
40t = 60t- 120
20t = 120
t = 6 hr
So, required distance = 60(6- 2) = 60 x 4 = 240k.m
Incorrect
Ans: c
Let the distance covered by freight and express trains be ‘x’ km in time ‘t’ hr and ‘t – 2’ hr, respectively.
According to the question,
40´ t 60x (t – 2)
40t = 60t- 120
20t = 120
t = 6 hr
So, required distance = 60(6- 2) = 60 x 4 = 240k.m
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Question 4 of 5
4. Question
If there is a policy that 1/3rd of a population of a community has migrated every year from one place to some other place, what is the leftover population of that community after the sixth year, if there is no further growth in the population during this period?
Correct
Ans: d
Leftover population after 6th year
= [1-(1/3)6 part of population
=[2/3]6 part of population
=[64/729]th part of population
Incorrect
Ans: d
Leftover population after 6th year
= [1-(1/3)6 part of population
=[2/3]6 part of population
=[64/729]th part of population
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Question 5 of 5
5. Question
The sum of income of A and B is more than that of C and D taken together. The sum of income of A and C is the same as that of B and D taken together. Moreover, A earns half as much as the sum of the income of B and D. Whose income is the highest?
Correct
Ans: b
According to question;
Income of (A + B)> Income of (C + D) …(i)
Income of (A + C) = Income of (B + D) …(ii)
And A = (B+D)/2 …………………………………..(iii)
From equation (iii),
2A = B +D …………………………………….(iv)
From equations (ii) and (iii),
2c = B+D
Now, from equations (iv) and (v);
2A = 2C
A=C
Now, from equation(i);
A+B>C+D
B>D [Because A =C]
Hence, B’s income is the highest.
Incorrect
Ans: b
According to question;
Income of (A + B)> Income of (C + D) …(i)
Income of (A + C) = Income of (B + D) …(ii)
And A = (B+D)/2 …………………………………..(iii)
From equation (iii),
2A = B +D …………………………………….(iv)
From equations (ii) and (iii),
2c = B+D
Now, from equations (iv) and (v);
2A = 2C
A=C
Now, from equation(i);
A+B>C+D
B>D [Because A =C]
Hence, B’s income is the highest.
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