[Mission 2022] Insta–DART (Daily Aptitude and Reasoning Test) 6 December 2021

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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Question 1 of 5

1. Question

A sailor sails a distance of 48 km along the flow of a river in 8 h. If it takes 12 h to return the same distance, then the speed of the flow of the river is

Correct

Sol : b)

Let speed of the flow of water be v km/h and rate of sailing of sailer be u km/h.

Then,

u+v= 48/8 ⇒ u+v = 6 ………………………………(1)

And u-v = 48/12 ⇒ u-v = 4 ………………….(2)

On solving Eqs. (1) and (2), we get

v=1 km/h

Incorrect

Sol : b)

Let speed of the flow of water be v km/h and rate of sailing of sailer be u km/h.

Then,

u+v= 48/8 ⇒ u+v = 6 ………………………………(1)

And u-v = 48/12 ⇒ u-v = 4 ………………….(2)

On solving Eqs. (1) and (2), we get

v=1 km/h

Question 2 of 5

2. Question

Ram sells his goods 20% cheaper than Bobby and 20% dearer than Chandilya. How much percentage is Chandilya’s goods cheaper/dearer than Bobby’s?

Correct

Sol. a)

If we take Ram as 100, we will get Bobby as 125 and Chandilya as 83.33. This means Chandilya’s goods are priced at 2/3rd Bobby’s and hence he sells his goods 33.33% cheaper than Bobby.

Incorrect

Sol. a)

If we take Ram as 100, we will get Bobby as 125 and Chandilya as 83.33. This means Chandilya’s goods are priced at 2/3rd Bobby’s and hence he sells his goods 33.33% cheaper than Bobby.

Question 3 of 5

3. Question

During winters, an athlete can run ‘x’ metres on one bottle of Glucose. But in the summer, he can only run 0.5 x metres on one bottle of Glucose. How many bottles of Glucose are required to run 400 metres during summer?

Correct

Sol. a)

1 Bottle → 0.5x metres

2 Bottles → 400 metres

Using unitary method, we get no. of bottles = 400/0.5x = 800/x Bottles.

Incorrect

Sol. a)

1 Bottle → 0.5x metres

2 Bottles → 400 metres

Using unitary method, we get no. of bottles = 400/0.5x = 800/x Bottles.

Question 4 of 5

4. Question

The seven digit number 876p37q is divisible by 225. The values of p and q can be respectively

Correct

Sol: d)

Seven digits number 876p37q is divisible by 225, then this number is also divisible by 9 and 25.

If this number is divisible by 9.

∴Sum of its digits is divisible by 9

Now, sum of digits= 8+ 7 + 6+ P+ 3+ 7+ q = 31+ p+q

p+q= 5 or p + q=14,q must be 5, if q= 5, p = 0 and 9

Incorrect

Sol: d)

Seven digits number 876p37q is divisible by 225, then this number is also divisible by 9 and 25.

If this number is divisible by 9.

∴Sum of its digits is divisible by 9

Now, sum of digits= 8+ 7 + 6+ P+ 3+ 7+ q = 31+ p+q

p+q= 5 or p + q=14,q must be 5, if q= 5, p = 0 and 9

Question 5 of 5

5. Question

Let x and y be positive integers such that x˃y. The expression 3x + 2y and 2x +3y, when divided by 5 leave remainders 2 and 3, respectively. What is the remainder when (x-y), is divided by 5?

Correct

Sol: a)

We have, 3x+2y is divided by 5 remainder is 2.

∴3x+2y=5q+2 ……………………..(1)

And 2x +3y is divided by 5 remainder is 3.

∴ 2x + 3y = 5m+3 ……………………..(2)

Subtract Eq. (2 ) from Eq.(1) , we get

x-y = 5(q-m)-1

x-y=5(q-m)-5+4

x-y=5(q-m-1)+4

∴x-y is divided by 5 remainder is 4.

Incorrect

Sol: a)

We have, 3x+2y is divided by 5 remainder is 2.

∴3x+2y=5q+2 ……………………..(1)

And 2x +3y is divided by 5 remainder is 3.

∴ 2x + 3y = 5m+3 ……………………..(2)

Subtract Eq. (2 ) from Eq.(1) , we get

x-y = 5(q-m)-1

x-y=5(q-m)-5+4

x-y=5(q-m-1)+4

∴x-y is divided by 5 remainder is 4.

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