Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
The population of a village is 1,00,000, Increase rate per annum is 10%. Find the population at the starting of the fourth year.
Correct
Sol. a)
100000 → 110000 (after 1 year) → 121000 (after 2 years) → 133100 (after 3 years and at the start of the fourth year).
Incorrect
Sol. a)
100000 → 110000 (after 1 year) → 121000 (after 2 years) → 133100 (after 3 years and at the start of the fourth year).
-
Question 2 of 5
2. Question
In the recent, climate conference in New York, out of 700 men, 500 women, 800 children present inside the building premises, 20% of the men, 40% of the women and 10% of the children were Indians. Find the percentage of people who were not Indian.
Correct
Sol. c)
Total people present = 700 + 500 + 800 = 2000.
Indians = 0.2 × 700 + 0.4 × 500 + 0.1 × 800 = 420 = 21% of the population. Thus, 79% of the people were not Indians.
Incorrect
Sol. c)
Total people present = 700 + 500 + 800 = 2000.
Indians = 0.2 × 700 + 0.4 × 500 + 0.1 × 800 = 420 = 21% of the population. Thus, 79% of the people were not Indians.
-
Question 3 of 5
3. Question
A train running at the speed of 72 km/h goes past a pole in 15 s. What is the length of the train?
Correct
Sol.(c)
Speed of train = Length of train / Time taken to cross the stationary object
Hence length of train = Speed of train × Time taken to cross the stationary object
= 72 × 1000 × 15/3600 = 300 m.
Incorrect
Sol.(c)
Speed of train = Length of train / Time taken to cross the stationary object
Hence length of train = Speed of train × Time taken to cross the stationary object
= 72 × 1000 × 15/3600 = 300 m.
-
Question 4 of 5
4. Question
Two cars A and B start simultaneously from a certain place at the speed of 30 km/h and 45 km/h, respectively. The car B reaches the destination 2 h earlier than A. What is the distance between the starting point and destination?
Correct
Sol.(b)
Let the time taken by car B to reach destination be x h.
So, the time taken by car A to reach destination is (x + 2) h.
Now, S1 (when distance is constant) T1 = S2, (when distance is constant) T2
30 × (x + 2)= 45 × x
30x + 60 = 45x
15x = 60
15 = 4h
Now, distance between starting point and destination S2T2
= 45 × 4 = 180 km.
Incorrect
Sol.(b)
Let the time taken by car B to reach destination be x h.
So, the time taken by car A to reach destination is (x + 2) h.
Now, S1 (when distance is constant) T1 = S2, (when distance is constant) T2
30 × (x + 2)= 45 × x
30x + 60 = 45x
15x = 60
15 = 4h
Now, distance between starting point and destination S2T2
= 45 × 4 = 180 km.
-
Question 5 of 5
5. Question
A sailor sails a distance of 48 km along the flow of a river in 8 h. If it takes 12 h to return the same distance, then the speed of the flow of the river is
Correct
Sol : (b)
Let speed of the flow of water be v km/h and rate of sailing of sailer be u km/h.
Then,
u+v= 48/8 Þ u+v = 6 ………………………………(1)
And u-v = 48/12 Þ u-v = 4 ………………….(2)
On solving Eqs. (1) and (2), we get
v=1 km/h
Incorrect
Sol : (b)
Let speed of the flow of water be v km/h and rate of sailing of sailer be u km/h.
Then,
u+v= 48/8 Þ u+v = 6 ………………………………(1)
And u-v = 48/12 Þ u-v = 4 ………………….(2)
On solving Eqs. (1) and (2), we get
v=1 km/h
Join our Official Telegram Channel HERE for Motivation and Fast Updates
Subscribe to our YouTube Channel HERE to watch Motivational and New analysis videos
