Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
The distance between two points (A and B) is 110 km. X starts running from point A at a speed of 60 km/h and Y starts running from point B at a speed of 40 km/h at the same time. They meet at a point C, somewhere on the line AB. What is the ratio of AC to BC?
Correct
Ans: a
Distance between two points= 110 km
Their relative speed = 60+ 40 = 100 km/h
Time after which they meet= Total distance/ Relative speed = 110/100 = 1.10 h
Distance covered by A in 1.10 h= AC = 60 x 1.10 = 66 km
Remaining distance = BC= 110- 66= 44 km
∴Required ratio = AC: BC= 66: 44= 3:2
Incorrect
Ans: a
Distance between two points= 110 km
Their relative speed = 60+ 40 = 100 km/h
Time after which they meet= Total distance/ Relative speed = 110/100 = 1.10 h
Distance covered by A in 1.10 h= AC = 60 x 1.10 = 66 km
Remaining distance = BC= 110- 66= 44 km
∴Required ratio = AC: BC= 66: 44= 3:2
-
Question 2 of 5
2. Question
Udit, a watch dealer, pays 20% custom tax on a foreign watch worth 500. For how much he should mark the price of watch, so that after allowing a discount of 10%, his net gain is 20%?
Correct
Ans : c
CP of watch after paying 20 % tax
= 500+ 500X 100
= ₹ 600
Profit percentage = 20 %
SP = 600 X 120/ 100
= ₹ 720
Let MRP be ₹x.
Now x – x * 10/ 100 =720
= 90x/100 = 720
= x=800
MRP = ₹ 800
Incorrect
Ans : c
CP of watch after paying 20 % tax
= 500+ 500X 100
= ₹ 600
Profit percentage = 20 %
SP = 600 X 120/ 100
= ₹ 720
Let MRP be ₹x.
Now x – x * 10/ 100 =720
= 90x/100 = 720
= x=800
MRP = ₹ 800
-
Question 3 of 5
3. Question
If 2m + 21+m = 24, then what is the value of m?
Correct
Ans: c
2m + 21+m = 24
⇒ 2m(1+2) =24
⇒2m * 3 = 24
⇒ 2m = 8 = 23
∴m=3
Incorrect
Ans: c
2m + 21+m = 24
⇒ 2m(1+2) =24
⇒2m * 3 = 24
⇒ 2m = 8 = 23
∴m=3
-
Question 4 of 5
4. Question
If the sum of an Integer and its reciprocal is 10/3, then the integer is equal to
Correct
Ans: a
Let the integer be x.
Now, by condition
Integer+Its reciprocal = 10/3
X+(1/x) = 10/3 ⇒(x2+1)/x = 10/3
3x2 + 3 = 10x ⇒ 3x2 – 10x +3 =0
3x2-9x-x+3=0 [by splitting the middle term]
3x(x-3)-1(x-3)=0 ⇒ (x-3)(3x-1)=0
∴x = 3 [since, 1/3 is not an integer]
Incorrect
Ans: a
Let the integer be x.
Now, by condition
Integer+Its reciprocal = 10/3
X+(1/x) = 10/3 ⇒(x2+1)/x = 10/3
3x2 + 3 = 10x ⇒ 3x2 – 10x +3 =0
3x2-9x-x+3=0 [by splitting the middle term]
3x(x-3)-1(x-3)=0 ⇒ (x-3)(3x-1)=0
∴x = 3 [since, 1/3 is not an integer]
-
Question 5 of 5
5. Question
Let x and y be positive integers such that x˃y. The expression 3x + 2y and 2x +3y, when divided by 5 leave remainders 2 and 3, respectively. What is the remainder when (x-y), is divided by 5?
Correct
Ans: a
We have, 3x+2y is divided by 5 remainder is 2.
∴3x+2y=5q+2 ……………………..(1)
And 2x +3y is divided by 5 remainder is 3.
∴2x + 3y = 5m+3 ……………………..(2)
Subtract Eq. (2 ) from Eq.(1) , we get
x-y = 5(q-m)-1
x-y=5(q-m)-5+4
x-y=5(q-m-1)+4
∴x-y is divided by 5 remainder is 4.
Incorrect
Ans: a
We have, 3x+2y is divided by 5 remainder is 2.
∴3x+2y=5q+2 ……………………..(1)
And 2x +3y is divided by 5 remainder is 3.
∴2x + 3y = 5m+3 ……………………..(2)
Subtract Eq. (2 ) from Eq.(1) , we get
x-y = 5(q-m)-1
x-y=5(q-m)-5+4
x-y=5(q-m-1)+4
∴x-y is divided by 5 remainder is 4.
Join our Official Telegram Channel HERE for Motivation and Fast Updates
Subscribe to our YouTube Channel HERE to watch Motivational and New analysis videos
