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Question 1 of 5
1. Question
A certain number of men can do a piece of work in 80 days. If there were 10 men less, It could be finished in 20 days more. How many men are there in the starting?
Correct
Answer : b
Let original number of men = X
Time taken by x = 80 days
Now, (x -10) men can finish the work n
(80+ 20) = 100 days
Here, M =x, M2 = (x – 10), D1 = B0
and D2= 100
According to the formula,
M1 D1 = M2 D2 [by Technique 1 ]
x*80= 100 * (x -10)
8x= 10x -100
10x-8x = 100
∴X= 50
Incorrect
Answer : b
Let original number of men = X
Time taken by x = 80 days
Now, (x -10) men can finish the work n
(80+ 20) = 100 days
Here, M =x, M2 = (x – 10), D1 = B0
and D2= 100
According to the formula,
M1 D1 = M2 D2 [by Technique 1 ]
x*80= 100 * (x -10)
8x= 10x -100
10x-8x = 100
∴X= 50
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Question 2 of 5
2. Question
20 men complete one-third of a work in 20 days. How many more men should be employed to finish the rest of work in 25 more days?
Correct
Answer : b
Given, M1 = 20
M2 = 20 +x
W1 = (1/3), W2 = 1-(1/3) = (2/3)
D1 = 20 and D2 = 25
According to the formula, M1 D1 W2 = M2 D2 W1
20 *20 *(2/3) = (20 + x ) * 25 *(1/3)
20* 20* (2/3) = (20 + x)* (25/3)
16 * 2 = 20 + x
∴X = 32 – 20 = 12
Incorrect
Answer : b
Given, M1 = 20
M2 = 20 +x
W1 = (1/3), W2 = 1-(1/3) = (2/3)
D1 = 20 and D2 = 25
According to the formula, M1 D1 W2 = M2 D2 W1
20 *20 *(2/3) = (20 + x ) * 25 *(1/3)
20* 20* (2/3) = (20 + x)* (25/3)
16 * 2 = 20 + x
∴X = 32 – 20 = 12
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Question 3 of 5
3. Question
In how many different ways, the letters of word FINANCE can be arranged?
Correct
Answer : d
Total number of letters =7, but N has come twice.
So, required number of arrangements
Incorrect
Answer : d
Total number of letters =7, but N has come twice.
So, required number of arrangements
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Question 4 of 5
4. Question
In how many ways, the letters of the word ‘BANKING’ can be arranged?
Correct
Answer : d
Total letters = 6, but R has come twice.
So, required number of arrangements
= (7!)/(2!)=(7* 6 *5 *4 *3* 2!)/2! = 2520
Incorrect
Answer : d
Total letters = 6, but R has come twice.
So, required number of arrangements
= (7!)/(2!)=(7* 6 *5 *4 *3* 2!)/2! = 2520
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Question 5 of 5
5. Question
The ratio of the ages of Ram and Rahim 10 yr ago was 1:3. The ratio of their ages five years hence will be 2:3. Then, the ratio of their present ages is
Correct
Answer : b
Let 10 yr ago, ages of Ram and Rahim
were x yr and 3x yr, respectively
Then, present age of Ram= (x+ 10)
and present age of Rahim = (3x + 10)
According to the question,
[(x+10+5)/(3x+10+5)] = (2/3)
3x + 45 = 6x + 30
3x=15
∴x = 5
Hence, required ratio = (5+10)/(3*5+10)
= (15/25) = 3:5
Incorrect
Answer : b
Let 10 yr ago, ages of Ram and Rahim
were x yr and 3x yr, respectively
Then, present age of Ram= (x+ 10)
and present age of Rahim = (3x + 10)
According to the question,
[(x+10+5)/(3x+10+5)] = (2/3)
3x + 45 = 6x + 30
3x=15
∴x = 5
Hence, required ratio = (5+10)/(3*5+10)
= (15/25) = 3:5
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