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Question 1 of 5
1. Question
Manoj takes twice as much time as Ajay and thrice as much as Vijay to finish a piece of Work. Together they finish the work in 1 day. What is the time taken by Manoj to finish the work?
Correct
Ans. (a)
M:A:V
2:1:2/3 or 6:3:2
Let Manoj takes 6x days Ajay takes 3x days
and vijay 2x days then 1/6x +1/3x+1/2x = 1
1/x[1/6+1/3+1/2]=1
1/x=1
So x = 1
Manoj will take 6 days
Incorrect
Ans. (a)
M:A:V
2:1:2/3 or 6:3:2
Let Manoj takes 6x days Ajay takes 3x days
and vijay 2x days then 1/6x +1/3x+1/2x = 1
1/x[1/6+1/3+1/2]=1
1/x=1
So x = 1
Manoj will take 6 days
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Question 2 of 5
2. Question
Apurva can do a piece of work in 12 days. Apurva and Amit complete the work together and were paid Rs. 54 and Rs. 81 respectively. How many days must they have taken to complete the work together?
Correct
Ans. (c)
Payment ratio= 54: 81
days work = 1/12:1/x
54:81 :: 1/12:1/x
81x 1/12 = 54 x 1/x
X = [(54×12)/81] x =8 days
together they will take = (1×8)/(12+8) = 4.8 days
Incorrect
Ans. (c)
Payment ratio= 54: 81
days work = 1/12:1/x
54:81 :: 1/12:1/x
81x 1/12 = 54 x 1/x
X = [(54×12)/81] x =8 days
together they will take = (1×8)/(12+8) = 4.8 days
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Question 3 of 5
3. Question
Raju is twice as efficient as Vijay Together, they finish the work in 14 days. In how many days can Vijay alone do the same work?
Correct
Ans. (C)
Let Raju can do the work in x days then vijay
in 2x days
together they can complete in
2x*x/3x= 14 days
x= 21 days, 2x =42 days
Incorrect
Ans. (C)
Let Raju can do the work in x days then vijay
in 2x days
together they can complete in
2x*x/3x= 14 days
x= 21 days, 2x =42 days
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Question 4 of 5
4. Question
If 12 men and 16 boys can do a piece of Work in 5 days and 13 men and 24 boys can do it in 4 days, compare the daily work done by a man with that done by a boy?
Correct
Ans. (c)
12 M+ 16B= 1/5………………………………………………..(1)
13 M+24 B (2) also
36 M+ 48 B = 3/5
36 M+48B=2/4
10 M = 1/10, M = 1/100
From eq (1) B = 1/200, M : B = 2:1
Incorrect
Ans. (c)
12 M+ 16B= 1/5………………………………………………..(1)
13 M+24 B (2) also
36 M+ 48 B = 3/5
36 M+48B=2/4
10 M = 1/10, M = 1/100
From eq (1) B = 1/200, M : B = 2:1
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Question 5 of 5
5. Question
A cistern is normally filled in 5 hours. However, it takes hours when there is leak in its bottom. If the cistern is full, in what time shall the leak empty it?
Correct
Ans. (D)
In one hour 1/5 part is filled now leak can
empty In x hour then
1/5 – 1/x = 1/6
⇒1/5 – 1/6=1/x
⇒1/30 = 1/x ⇒x = 30 hours
Incorrect
Ans. (D)
In one hour 1/5 part is filled now leak can
empty In x hour then
1/5 – 1/x = 1/6
⇒1/5 – 1/6=1/x
⇒1/30 = 1/x ⇒x = 30 hours
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