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Question 1 of 5
1. Question
At present, the ratio of the ages of Maya and Chhaya is 6:5 and fifteen years from now, the ratio will get changed to 9:8 Maya’s present age is
Correct
Answer : c
Let the present ages of Maya and Chhaya are 6x and 5x yr, respectively.
According tpo the question,
After 15 yr,
[(6x+15)/(5x+15)] = (9/8)
48x +120=45x +135
3x = 15
∴x = 5
Hence, present age of Maya = 5 x6 = 30 yr
Incorrect
Answer : c
Let the present ages of Maya and Chhaya are 6x and 5x yr, respectively.
According tpo the question,
After 15 yr,
[(6x+15)/(5x+15)] = (9/8)
48x +120=45x +135
3x = 15
∴x = 5
Hence, present age of Maya = 5 x6 = 30 yr
-
Question 2 of 5
2. Question
3 yr before, the average age of a family of 5 members was 17 yr. Due to birth of a new child, the average age is same today. The present age of child is
Correct
Answer : d
3yr before,
Total age of 5 members
=17 x5 = 85 yr
∴The present age of all members of family
85+3 x5 100 yr
Let the age of child be x yr.
∴Present average age of family including
the child
=(100+x)/6
17 = (100+x)/6
∴x = 102 – 100 = 2 yr
Incorrect
Answer : d
3yr before,
Total age of 5 members
=17 x5 = 85 yr
∴The present age of all members of family
85+3 x5 100 yr
Let the age of child be x yr.
∴Present average age of family including
the child
=(100+x)/6
17 = (100+x)/6
∴x = 102 – 100 = 2 yr
-
Question 3 of 5
3. Question
If the three-fourth of a number is subtracted from the number, the value so obtained is 163. What is that number?
Correct
Answer : d
Let the number be x .
According to the question,
x– x * (3/4) = 163
(x/4) = 163
∴x = 652
Incorrect
Answer : d
Let the number be x .
According to the question,
x– x * (3/4) = 163
(x/4) = 163
∴x = 652
-
Question 4 of 5
4. Question
A positive number, when increased by 10 equals 200 times its reciprocal. What 1s the number?
Correct
Answer : b
Let the positive number be x,
According to the question,
X + 10 = (200/x)
Incorrect
Answer : b
Let the positive number be x,
According to the question,
X + 10 = (200/x)
-
Question 5 of 5
5. Question
There are two examination halls P and Q. If 10 students shifted P to Q , then the number of students will be equal in both the examination halls. If 20 students shifted from Q to P, then the students of P would be doubled to the students of Q . The numbers of students would be in P and Q, respectively are
Correct
Answer : d
Let number of students in examination
halls P and Q is x and y respectively.
Then, as per the first condition,
x-10= y + 10
x-y= 20 …………………………………………..(1)
As per the second condition,
x+ 20 = 2(y- 20)
x+20 = 2y-40
x-2y= -60 ……………………………………………..(2)
On subtracting Eq. (2) from Eq. (1), we get
-y+ 2y= 20+60
y= 80
Putting the value of y in Eq. (1). we get
x-80=20
x= 100
Hence, number of students in examination
halls P and Q is 100 and 80, respectivelym
Incorrect
Answer : d
Let number of students in examination
halls P and Q is x and y respectively.
Then, as per the first condition,
x-10= y + 10
x-y= 20 …………………………………………..(1)
As per the second condition,
x+ 20 = 2(y- 20)
x+20 = 2y-40
x-2y= -60 ……………………………………………..(2)
On subtracting Eq. (2) from Eq. (1), we get
-y+ 2y= 20+60
y= 80
Putting the value of y in Eq. (1). we get
x-80=20
x= 100
Hence, number of students in examination
halls P and Q is 100 and 80, respectivelym
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