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Question 1 of 5
1. Question
The ratio between the present ages of A and B is 4:5. If the ratio between their ages 4 yr hence becomes 14:17, then what is B’s age at present?
Correct
Answer : a
Let the ages of A and B are 4x and 5x yr, respectively
According to the question,
According to the question,
(4x+4)/5x+4) =(14/17)
68x+68 = 70x +56
2x = 12
X=6
Hence, present age of B = 5 x 6 = 30 yr
Incorrect
Answer : a
Let the ages of A and B are 4x and 5x yr, respectively
According to the question,
According to the question,
(4x+4)/5x+4) =(14/17)
68x+68 = 70x +56
2x = 12
X=6
Hence, present age of B = 5x 6 = 30 yr
-
Question 2 of 5
2. Question
The present ages of two persons are 36 and 50 yr, respectively. If after n yr the ratio of their ages will be 3: 4, then the value of n is
Correct
Answer : d
According to the question,
(36+n)/(50+n) = (3/4)
144 + 4n = 150 + 3n
∴n = 6
Incorrect
Answer : d
According to the question,
(36+n)/(50+n) = (3/4)
144 + 4n = 150 + 3n
∴n = 6
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Question 3 of 5
3. Question
The ratio of the ages of Ram and Rahim 10 yr ago was 1:3. The ratio of their ages five years hence will be 2:3. Then, the ratio of their present ages is
Correct
Answer : b
Let 10 yr ago, ages of Ram and Rahim
were x yr and 3x yr, respectively
Then, present age of Ram= (x+ 10)
and present age of Rahim = (3x + 10)
According to the question,
[(x+10+5)/(3x+10+5)] = (2/3)
3x + 45 = 6x + 30
3x=15
∴x = 5
Hence, required ratio = (5+10)/(3×5+10)
= (15/25) = 3:5
Incorrect
Answer : b
Let 10 yr ago, ages of Ram and Rahim
were x yr and 3x yr, respectively
Then, present age of Ram= (x+ 10)
and present age of Rahim = (3x + 10)
According to the question,
[(x+10+5)/(3x+10+5)] = (2/3)
3x + 45 = 6x + 30
3x=15
∴x = 5
Hence, required ratio = (5+10)/(3×5+10)
= (15/25) = 3:5
-
Question 4 of 5
4. Question
If a number is multiplied by three-fourth of itself, the value thus obtained is 10800. What is that number?
Correct
Answer : c
Incorrect
Answer : c
-
Question 5 of 5
5. Question
The difference between two numbers is 18. If four times the second number is less than three times the first number by 18, then what is the sum of these two numbers?
Correct
Answer : d
Let first number =x
and second number = y
According to the question,
x – y = 18 …………………(1)
and 3x – 4y = 18 ………………….(2)
On multiplying Eq. (1) by 3 and then
subtracting Eq. (ii) from it, we get
3x-3y 54
3x-4y = 18
y= 36
On putting the value of y in Eq. (1), we get
x = 18 + y = 18 + 36
x = 54
Required sum = x + y = 54+ 36= 90
Incorrect
Answer : d
Let first number =x
and second number = y
According to the question,
x – y = 18 …………………(1)
and 3x – 4y = 18 ………………….(2)
On multiplying Eq. (1) by 3 and then
subtracting Eq. (ii) from it, we get
3x-3y 54
3x-4y = 18
y= 36
On putting the value of y in Eq. (1), we get
x = 18 + y = 18 + 36
x = 54
Required sum = x + y = 54+ 36= 90
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