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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
A boat sails down the river 10 km and then up the river for 6 km. The speed of the river flow is 1 km/h. What should be the minimum speed of the boat for the trip to take a maximum of 4 hours?
Correct
Ans. (D)
D1/(SB+SS) +[D2/(SB-SS)] = 4 hour
10/(SB+1)]+[6/(SB-1)]=4 hour………………………….(1)
Going by option and (1) we get
SB = 4km/hour
Incorrect
Ans. (D)
D1/(SB+SS) +[D2/(SB-SS)] = 4 hour
10/(SB+1)]+[6/(SB-1)]=4 hour………………………….(1)
Going by option and (1) we get
SB = 4km/hour
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Question 2 of 5
2. Question
Two trains are running on parallel lines in the same direction at speeds of 40 kmph and 20 kmph respectively. The faster train crosses a man in the second train in 36 seconds. The length of the faster train is
Correct
Ans: (a)
T = time required
LT+LO/(ST-SO)……………………………….(1)
ST-SO=40-20=20km/h
=20(5/18)=(50/9)m/s
Now t = (LT/50)/9 Þ36 = (LT/50)/9
So, LT = 200m
Incorrect
Ans: (a)
T = time required
LT+LO/(ST-SO)……………………………….(1)
ST-SO=40-20=20km/h
=20(5/18)=(50/9)m/s
Now t = (LT/50)/9 Þ36 = (LT/50)/9
So, LT = 200m
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Question 3 of 5
3. Question
The speed of the boat in still water is 12 km/h and the speed of the stream is 2 km/h. A distance of 8 km, going upstream, is covered in
Correct
Ans. (d)
T = D/(SB-SS)(upstream)
=8/(12-2)=8/10=(8/10 )60 = 48 min
Incorrect
Ans. (d)
T = D/(SB-SS)(upstream)
=8/(12-2)=8/10=(8/10 )60 = 48 min
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Question 4 of 5
4. Question
A boat goes 15 km upstream in 80 minutes. The speed of the stream is 5 km/h. The speed of the boat in still water is
Correct
Ans. (B)
t = D /(SB-SS)(upstream)
80/60 = 15/(SB-5) Þ4/3 = 15/(SB-5)
SB = 16.25 km/h
Incorrect
Ans. (B)
t = D /(SB-SS)(upstream)
80/60 = 15/(SB-5) Þ4/3 = 15/(SB-5)
SB = 16.25 km/h
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Question 5 of 5
5. Question
Two trains are travelling in the same direction at 50 km/h and 30 km/h respectively. The faster train crosses a man in the slower train in 18 seconds. Find the length of the faster train.
Correct
Ans: (a)
T = (LT+LO)/(ST-SO)
50-30 = 20km/hr=50/9 m/s
Now 18 = LT/(50/9)ÞLT = 100 m
Incorrect
Ans: (a)
T = (LT+LO)/(ST-SO)
50-30 = 20km/hr=50/9 m/s
Now 18 = LT/(50/9)ÞLT = 100 m
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