[Mission 2022] Insta–DART (Daily Aptitude and Reasoning Test) 01 October 2021

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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Question 1 of 5

1. Question

There are 6 tasks and 6 people. Task 1 cannot be assigned either to person 1 or to person 2; task 2 must be assigned to either person 3 or person 4. Every person is to be assigned one task. In how many ways can the assignment be done?

Correct

Correct Answer : A

Explanation:

Task 1 can not be assigned to either person 1 or 2 i.e. there are 4 options. Task 2 can be assigned to 3 or 4.

So, there are only 2 options for task 2.

So required no. of ways =

2 options for task 2

3 options for task 1

4 options for task 3

3 options for task 4

2 options for task 5

1 option for task 6.

Total ways = 2 × 3 × 4 × 3 × 2 × 1 = 144

Incorrect

Correct Answer : A

Explanation:

Task 1 can not be assigned to either person 1 or 2 i.e. there are 4 options. Task 2 can be assigned to 3 or 4.

So, there are only 2 options for task 2.

So required no. of ways =

2 options for task 2

3 options for task 1

4 options for task 3

3 options for task 4

2 options for task 5

1 option for task 6.

Total ways = 2 × 3 × 4 × 3 × 2 × 1 = 144

Question 2 of 5

2. Question

In a chess competition involving some boys and girls of a school, every student had to play exactly one game with every other student. It was found that in 45 games both the players were girls and in 190 games both were boys. The number of games in which one player was a boy and the other was a girl is

Correct

Correct Answer : A

Explanation:

Let number of girls = x

The number of boys = y

45 games in which both the players were girls xC2 = 45

x! / 2!(x-2)! = x(x-1) = 90

Therefore, x = 10.

Incorrect

Correct Answer : A

Explanation:

Let number of girls = x

The number of boys = y

45 games in which both the players were girls xC2 = 45

x! / 2!(x-2)! = x(x-1) = 90

Therefore, x = 10.

Question 3 of 5

3. Question

Each of two women and three men is to occupy one chair out of eight chairs, each of which numbered from 1 to 8. First, women are to occupy any two chairs from those numbered 1 to 4; and then the three men would occupy any, three chairs out of the remaining six chairs. What is the maximum number of different ways in which this can be done?

Correct

Correct Answer : C

Explanation:

2 Women can occupy 2 chairs out of the first four chairs in 4P2 ways. 3 men can be arranged in the remaining 6 chairs in 6P3 ways. Hence, total no. of ways = 4P2 × 6P3 = 1440

Incorrect

Correct Answer : C

Explanation:

2 Women can occupy 2 chairs out of the first four chairs in 4P2 ways. 3 men can be arranged in the remaining 6 chairs in 6P3 ways. Hence, total no. of ways = 4P2 × 6P3 = 1440

Question 4 of 5

4. Question

-‘X’ is twice as old as ‘Y’ 3 years ago, when ‘X’ was as old as ‘Y’ today. If the difference between their ages as present is 3 years, how old is ‘X’ at present?

Correct

Correct Answer : C

Explanation:

Let present age of X = x years Present age of Y = (x – 3) years

3 years ago, age of X = (x – 3) years Age of Y = (x – 6) years

According to the question, x – 3 = 2(x – 6)

x – 3 = 2x – 12

12 – 3 = 2x – x

x = 9 years

Incorrect

Correct Answer : C

Explanation:

Let present age of X = x years Present age of Y = (x – 3) years

3 years ago, age of X = (x – 3) years Age of Y = (x – 6) years

According to the question, x – 3 = 2(x – 6)

x – 3 = 2x – 12

12 – 3 = 2x – x

x = 9 years

Question 5 of 5

5. Question

A candidate attempted 12 questions and secured full marks in all of them. If he obtained 60% in the test and all questions carry equal marks, then what is the number of questions in the test?

Correct

Ans-D

Let total no. of questions be x.

Now, Right questions = 12 = 60% of x. 0.6x = 12

x = 20

Incorrect

Ans-D

Let total no. of questions be x.

Now, Right questions = 12 = 60% of x. 0.6x = 12

x = 20

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