[Mission 2022] Insta–DART (Daily Aptitude and Reasoning Test) 30 September 2021

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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Question 1 of 5

1. Question

In a row of 40 girls, when Komal was shifted to her left by 4 places her number from the left end of the row became 10. What was the number of Swati from the right end of the row if Swati was three places to the right of Komal’s original positions.?

Correct

Ans:- d

Sol:- On shifting 4 the left Komal is 10th from the left end of the row. Thus, komal’s original position was 14th from the left end. Swati is 3 places to the right of Komal’s original positions Clearly, swati is 14 + 3 = 17 th from the left end. Number of girls to the right of swati = (40 – 17) = 23. Thus, Swati is 24th from the right end of the row.

Incorrect

Ans:- d

Sol:- On shifting 4 the left Komal is 10th from the left end of the row. Thus, komal’s original position was 14th from the left end. Swati is 3 places to the right of Komal’s original positions Clearly, swati is 14 + 3 = 17 th from the left end. Number of girls to the right of swati = (40 – 17) = 23. Thus, Swati is 24th from the right end of the row.

Question 2 of 5

2. Question

In the month of July of a certain year, the average daily expenditure of an organisation was Rs. 68. For the first 15 days of the month, the average daily expenditure was 85 and for the last 17 days, Rs. 51. Find the amount spent by the organisation on the 15th of the month.

Correct

Ans-c

Obviously, the 15th day is being double counted. Calculations can be reduced by thinking as: Surplus in first 15 days Deficit in last 17 days = 255-289 ® Net deficit of 34. This means that the average is reducing by 34 due to the double counting of the 15th day. This can only mean that the 15^{th} day’s expenditure is Rs. 68 -34= 34.

Incorrect

Ans-c

Obviously, the 15th day is being double counted. Calculations can be reduced by thinking as: Surplus in first 15 days Deficit in last 17 days = 255-289 ® Net deficit of 34. This means that the average is reducing by 34 due to the double counting of the 15th day. This can only mean that the 15^{th} day’s expenditure is Rs. 68 -34= 34.

Question 3 of 5

3. Question

In 1919, W. Rhodes, the Yorkshire cricketer, scored 891 runs for his county at an average of 34.27; in 1920, he scored 949 runs at an average of 28.75; in 1921, 1329 runs at an average of 42.87 and in 1922, 1101 runs at an average of 36.70. What was his county batting average for the four years?

Correct

Ans-d

Find out the number of innings in each year Then the answer will be given by [Total runs in 4 years / Total innings in 4 years ] (4270/119 = 35.88)

Incorrect

Ans-d

Find out the number of innings in each year Then the answer will be given by [Total runs in 4 years / Total innings in 4 years ] (4270/119 = 35.88)

Question 4 of 5

4. Question

A train travels with a speed of 20 m/s in the first 10 minutes, goes 8.5 km in the next 10 minutes, 11 km in the next 10, 8.5 km in the next 10 and 6 km in the next 10 minutes. What is the average speed of the train in kilometre per hour for the journey described?

Correct

Ans-d

Find the total distance covered in each segment of 10 minutes, You will get total distance= 46 kilometres in 50 mins.

Incorrect

Ans-d

Find the total distance covered in each segment of 10 minutes, You will get total distance= 46 kilometres in 50 mins.

Question 5 of 5

5. Question

In a mixture of 80 litres of milk and water, 25% of the mixture is milk. How much water should be added to the mixture so that milk becomes 20% of the mixture?

Correct

Ans-a

From the first statement we get that out of 80 litres of the mixture, 20 litres must be milk. Since, we are adding water to this and keeping the milk constant, it is quite evident that 20 litres of milk should correspond to 20% of the total mixture. Thus, the amount in the total mixture must be 100, which means we need to add 20 litres of water to make 100 litres of the mixture.

Incorrect

Ans-a

From the first statement we get that out of 80 litres of the mixture, 20 litres must be milk. Since, we are adding water to this and keeping the milk constant, it is quite evident that 20 litres of milk should correspond to 20% of the total mixture. Thus, the amount in the total mixture must be 100, which means we need to add 20 litres of water to make 100 litres of the mixture.

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