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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
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Question 1 of 5
1. Question
The speeds of three buses are in the ratio 2:3:4. The time taken by these buses to travel the same distance will be in ratio.
Correct
Ans: d
Let the distance be x.
Now, ratio of time taken the distance by each bus
= x/2:x/3:x/4=12/2:12/3:12/4 = 6:4:3
Incorrect
Ans: d
Let the distance be x.
Now, ratio of time taken the distance by each bus
= x/2:x/3:x/4=12/2:12/3:12/4 = 6:4:3
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Question 2 of 5
2. Question
There are 48 cricket balls, 72 hockey balls and 84 tennis balls and they have to be arranged in several rows in such a way that every row contains the same number of balls of one type. What is the minimum number of rows required for this to happen?
Correct
Ans: c
Given number of cricket balls= 48= 24 x3
Number of hockey balls = 72 = 23x 32
And number of tennis balls = 84=22x 3×7
∴HCF of 48, 72 and 84 = 22 x 3= 12
Now, minimum number of rows= (48/12)+(72/12)+(84/12)=4+6+7=17
Incorrect
Ans: c
Given number of cricket balls= 48= 24 x3
Number of hockey balls = 72 = 23x 32
And number of tennis balls = 84=22x 3×7
∴HCF of 48, 72 and 84 = 22 x 3= 12
Now, minimum number of rows= (48/12)+(72/12)+(84/12)=4+6+7=17
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Question 3 of 5
3. Question
In a class of 60, where girls are twice that of boys, Kamal ranked seventeenth from the top. If there are 9 girls ahead of Kamal, how many boys are after him in rank?
Correct
Correct Answer : C
Answer Justification : Explanation: Let the number of boys be x. Then, number of girls = 2x.
x + 2x = 60 or 3x = 60 or x = 20. So, number of boys = 20 and number of girls = 40.
Number of students behind Kamal in rank (60 – 17) =43. Number of girls ahead of Kamal in rank = 9. Number of girls behind Kamal in rank = (40 – 9) = 31 Number of boys behind Kamal in rank = (43 – 31) = 12.
Incorrect
Correct Answer : C
Answer Justification : Explanation: Let the number of boys be x. Then, number of girls = 2x.
x + 2x = 60 or 3x = 60 or x = 20. So, number of boys = 20 and number of girls = 40.
Number of students behind Kamal in rank (60 – 17) =43. Number of girls ahead of Kamal in rank = 9. Number of girls behind Kamal in rank = (40 – 9) = 31 Number of boys behind Kamal in rank = (43 – 31) = 12.
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Question 4 of 5
4. Question
The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner?
Correct
Ans-Correct answer: B
Clearly, every member except one (i.e., the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 – 1 = 29.
Incorrect
Ans-Correct answer: B
Clearly, every member except one (i.e., the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 – 1 = 29.
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Question 5 of 5
5. Question
A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes?
Correct
Correct answer D
Number of cuts made to cut a roll into 10 pieces = 9. Therefore, required number of rolls = (45 × 24)/9 = 120.
Incorrect
Correct answer D
Number of cuts made to cut a roll into 10 pieces = 9. Therefore, required number of rolls = (45 × 24)/9 = 120.
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