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Question 1 of 5
1. Question
(x+y) : (x-y)=3:5 and xy = positive imply that
Correct
Ans: d
Given that, (x+y) : (x-y) = 3:5
(x+y)/(x-y) = 3/5
Applying componendo and dividend rule, we get
[(x+y)+(x-y)]/[(x+y)-(x-y)] = (3+5)/(3-5)
2x/2y = 8/-2
x/y = -4
∴x= -4y
But it is given, xy = Positive
∴-4yxy = Positive
-4y2 = Poitive, which is not possible.
Hence, no real solution for x and y exist.
Incorrect
Ans: d
Given that, (x+y) : (x-y) = 3:5
(x+y)/(x-y) = 3/5
Applying componendo and dividend rule, we get
[(x+y)+(x-y)]/[(x+y)-(x-y)] = (3+5)/(3-5)
2x/2y = 8/-2
x/y = -4
∴x= -4y
But it is given, xy = Positive
∴-4yxy = Positive
-4y2 = Poitive, which is not possible.
Hence, no real solution for x and y exist.
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Question 2 of 5
2. Question
If A:B = 2:3, B:C = 5:7 and C:D = 3: 10, then what is A 😀 equal to?
Correct
Ans: a
Given, A:B = 2:3, B:C = 5:7 and C:D = 3:10
(A/D)= (A/B)x (B/C) ×(C/D)= (2/3) x(5/7)x (3/10) = 1/7
A:D = 1:7
Incorrect
Ans: a
Given, A:B = 2:3, B:C = 5:7 and C:D = 3:10
(A/D)= (A/B)x (B/C) ×(C/D)= (2/3) x(5/7)x (3/10) = 1/7
A:D = 1:7
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Question 3 of 5
3. Question
If a, b, c, d and e are in continued proportion, then a/e is equal to
Correct
Since, a, b, c, d and e are in continued proportion
∴a/b = b/c = c/d = d/e
e/d = d/c = c/b = b/a
∴c= b2/a
[because c/b = b/a]
∴d = c2/b = (b4/a2).(1/b = b3/a3
∴e = d2/c =( b6/a4).(a/b2) = b4/a3
a/e = a/(b4/a3) = a4/b4
Incorrect
Since, a, b, c, d and e are in continued proportion
∴a/b = b/c = c/d = d/e
e/d = d/c = c/b = b/a
∴c= b2/a
[because c/b = b/a]
∴d = c2/b = (b4/a2).(1/b = b3/a3
∴e = d2/c =( b6/a4).(a/b2) = b4/a3
a/e = a/(b4/a3) = a4/b4
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Question 4 of 5
4. Question
In a certain school, the ratio of boys to girls is 7:5. If there are 2400 students in the school, then how many girls are there?
Correct
Ans: d
Let the number of boys and girls be 7x and 5x, respectively.
Given, total number of students = 2400
7x + 5x = 2400
12x = 2400
x=200
Required number of girls = 5x = 5´ 200 = 1000
Incorrect
Ans: d
Let the number of boys and girls be 7x and 5x, respectively.
Given, total number of students = 2400
7x + 5x = 2400
12x = 2400
x=200
Required number of girls = 5x = 5´ 200 = 1000
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Question 5 of 5
5. Question
Age of X is six times that of Y. After 4 yr, X is four times elder to Y. What is the present age of Y?
Correct
Ans: c
Let the age of X and Y be x and y, respectively.
X=6y
Then, (x+4)=4(y+4)
6y+4=4y+16
2y=12
∴y=6
So, the present age of Y is 6 yr.
Incorrect
Ans: c
Let the age of X and Y be x and y, respectively.
X=6y
Then, (x+4)=4(y+4)
6y+4=4y+16
2y=12
∴y=6
So, the present age of Y is 6 yr.
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