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Question 1 of 5
1. Question
If a:b = 3:5 and b:c = 7:8, then 2a:3b:7c is equal to
Correct
Ans: c
We have, a/b = 3/5
Because b=5a/3 and b/c = 7/8
C=(8/7)a = (8/7)´(5a/3) = 40a/21
Because a:b:c = a:5a/3 :40a/21
Now, 2a:3b:7c=2a:5a:( 40a/3) = 2:5( 40a)/3 = 6:15:40
Incorrect
Ans: c
We have, a/b = 3/5
Because b=5a/3 and b/c = 7/8
C=(8/7)a = (8/7)´(5a/3) = 40a/21
Because a:b:c = a:5a/3 :40a/21
Now, 2a:3b:7c=2a:5a:( 40a/3) = 2:5( 40a)/3 = 6:15:40

Question 2 of 5
2. Question
The speeds of three buses are in the ratio 2:3:4. The time taken by these buses to travel the same distance will be in ratio.
Correct
Ans: d
Let the distance be x.
Now, ratio of time taken the distance by each bus
= x/2:x/3:x/4=12/2:12/3:12/4 = 6:4:3
Incorrect
Ans: d
Let the distance be x.
Now, ratio of time taken the distance by each bus
= x/2:x/3:x/4=12/2:12/3:12/4 = 6:4:3

Question 3 of 5
3. Question
In a mixture of milk and water of volume 30 L, the ratio of milk and water is 7:3. The quantity of water to be added to the mixture to make the ratio of milk and water 1:2 is
Correct
Ans: c
Since, milk = 7x and water = 3x
Then, 7x + 3x = 30
10x = 30
\x = 3
So, milk= 21L and water = 9L
Let y L of water to be added.
Then, 21/(9+y) =1/2
9+y = 42
Y=33L
Incorrect
Ans: c
Since, milk = 7x and water = 3x
Then, 7x + 3x = 30
10x = 30
\x = 3
So, milk= 21L and water = 9L
Let y L of water to be added.
Then, 21/(9+y) =1/2
9+y = 42
Y=33L

Question 4 of 5
4. Question
The ratio of ages of A and B is 2:5 and the ratio of ages of B and C is 3:4. What is the ratio of ages of A, B and C?
Correct
Ans: a
Given, ratio of ages of A and B i.e A:B = 2:5
Ratio of ages of B and C = 3:4
\Ratio of ages of A,B and C =
= 2 x 3:3x 5:5 x 4 = 6:15:20

Question 5 of 5
5. Question
(X+y) :(xy)=3:5 and any xy = positive imply that
Correct
Solution: B
Ans:d
Given that, (x+y):/9xy)=3:5
\(x+y)/(xy)=3/5
Applying componendo and dividend rule, we get
[(x+y)+(xy)]/[(x+y)(xy)] = (3+5)/(35)
2x/2y = 8/2
x/y = 4
∴x=4y
But it is given, xy = positive
∴4yx y = Positive
4y^{2} = Positive, which is not possible
Hence, no real solution for x and y exist.
One person sits between T and J
Incorrect
Solution: B
Ans:d
Given that, (x+y):/9xy)=3:5
\(x+y)/(xy)=3/5
Applying componendo and dividend rule, we get
[(x+y)+(xy)]/[(x+y)(xy)] = (3+5)/(35)
2x/2y = 8/2
x/y = 4
∴x=4y
But it is given, xy = positive
∴4yx y = Positive
4y^{2} = Positive, which is not possible
Hence, no real solution for x and y exist.
One person sits between T and J
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