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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
1/48 of a work is completed in half a day by 5 personas. Then, 1/40 of the work can be completed by 6 persons in how many days?
Correct
Ans: d
Because M1D1/W1 = M2D2/W2
(5(1/2))/(1/48) = (6xD2)/1/40
D2= [(1/2)x5x48]/(40×6)=1/2
Incorrect
Ans: d
Because M1D1/W1 = M2D2/W2
(5(1/2))/(1/48) = (6xD2)/1/40
D2= [(1/2)x5x48]/(40×6)=1/2
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Question 2 of 5
2. Question
A can do a piece of work in 24 days. If B is 60% more efficient than A, then how many days does B require to do the same work?
Correct
Ans: a
⇒n1D1 = n2D2⇒100×24 = 160xD2
∴D2 = (100×24)/160 = 15 days
Incorrect
Ans: a
⇒n1D1 = n2D2⇒100×24 = 160xD2
∴D2 = (100×24)/160 = 15 days
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Question 3 of 5
3. Question
A garrison of ‘n’ men had enough food to last for 30 days. After 10 days, 50 more men joined them. If the food now lasted for 16 days, then what is the value of n?
Correct
Ans: a
By given condition, n x 30 = n x10+(n+50)x16
⇒20n = 16n + 800 ⇒n=(800/4) = 200
Incorrect
Ans: a
By given condition, n x 30 = n x10+(n+50)x16
⇒20n = 16n + 800 ⇒n=(800/4) = 200
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Question 4 of 5
4. Question
Four taps can individually fill a cistern of water in 1h, 2h, 3h and 6h, respectively. If all the four taps are opened simultaneously, then the cistern can be filled in how many minutes?
Correct
Ans:b
Required time = 1/[(1/1)+(1/2)+(1/3)+(1/6)] = 6/(6+3+2+1)
=6/12h = (6/12 )60 min = 30 min
Incorrect
Ans:b
Required time = 1/[(1/1)+(1/2)+(1/3)+(1/6)] = 6/(6+3+2+1)
=6/12h = (6/12 )60 min = 30 min
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Question 5 of 5
5. Question
X completes a job in 2 days and Y completes it in 3 days and Z takes 4 days to complete it. If they work together and get 3900 for the job, then how much amount does Y get?
Correct
Ans: b
Ratio of work done by X, Y and Z = 1/2 : 1/3 : ¼ = 6:4:3
Now, ratio in their amount = 6:4:3
∴Part of Y = [4/(6+4+3)] x 3900=Rs. 1200
Incorrect
Ans: b
Ratio of work done by X, Y and Z = 1/2 : 1/3 : ¼ = 6:4:3
Now, ratio in their amount = 6:4:3
∴Part of Y = [4/(6+4+3)] x 3900=Rs. 1200
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