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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
A cricket team of 11 players is to be formed from 20 players including 6 bowlers and 3 wicket keepers, The number of ways in which a team can be formed having exactly 4 bowlers and 2 wicket keepers is
Correct
Ans: a
There are 6 bowlers, 3 wicket keepers and 11 batsman in all. The number of ways in which a team of 4 bowlers, 2 wicket keepers and 5 batsman can be chosen.
= 6C4 x 3C2 x 11C5
= (6 x5)/(2 x 1) x 3 x (11 x 10 x 9 x 8 x 7)/(5 x 4 x 3 x 2 x 1) =20790
Incorrect
Ans: a
There are 6 bowlers, 3 wicket keepers and 11 batsman in all. The number of ways in which a team of 4 bowlers, 2 wicket keepers and 5 batsman can be chosen.
= 6C4 x 3C2 x 11C5
= (6 x5)/(2 x 1) x 3 x (11 x 10 x 9 x 8 x 7)/(5 x 4 x 3 x 2 x 1) =20790
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Question 2 of 5
2. Question
In a hockey championship, there were 153 matches played Every two teams played one match with each other. The number of teams participating in the championship is
Correct
Ans: B
= 18C2 = (18 x 17)/2 = 153
Incorrect
Ans: B
= 18C2 = (18 x 17)/2 = 153
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Question 3 of 5
3. Question
Seven points lie on a circle How many chords can be drawn by joining these points.
Correct
Ans: b
Number of chords =7C2 = 21
Incorrect
Ans: b
Number of chords =7C2 = 21
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Question 4 of 5
4. Question
Ten different letters of an alphabet are given. Words with 5 letters are formed from these given letters. Then the number of words which have at least one letter repeated is
Correct
Ans: a
Possible number of words formed =
Number of words without repetition =10P5
Thus number of words having at least one letter repeated is
–10P5 = 69760
Incorrect
Ans: a
Possible number of words formed =
Number of words without repetition =10P5
Thus number of words having at least one letter repeated is
–10P5 = 69760
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Question 5 of 5
5. Question
The value of 10C4 + 10C5 is
Correct
Ans: a
=10C4 + 10C5 = 11C5=462
Incorrect
Ans: a
=10C4 + 10C5 = 11C5=462
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