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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Read the following information carefully and answer the questions below it. Life was not easy before Aryabhatta. Zero was not invented and also people could not multiply numbers. Thus mathematics had only 9 digits (1 to 9) and after that came 11 and so on. Find the answer to following operations in mathematics used then
What is 7+ 11+3=?
Correct
Ans: c
Replace 10 by 11, 20 by 22 and so on.
7 +11 +3 is actually 7 + 10 +3 = 20
Which is 22
Incorrect
Ans: c
Replace 10 by 11, 20 by 22 and so on.
7 +11 +3 is actually 7 + 10 +3 = 20
Which is 22
-
Question 2 of 5
2. Question
Read the following information carefully and answer the questions below it. Life was not easy before Aryabhatta. Zero was not invented and also people could not multiply numbers. Thus mathematics had only 9 digits (1 to 9) and after that came 11 and so on. Find the answer to following operations in mathematics used then
What is 21 +29+ 1 = ?
Correct
Ans: c
Replace 10 by 11, 20 by 22 and so on.
21 +29+1 is actually 19 +27+ 1 = 47
which is 52
Incorrect
Ans: c
Replace 10 by 11, 20 by 22 and so on.
21 +29+1 is actually 19 +27+ 1 = 47
which is 52
-
Question 3 of 5
3. Question
Read the following information carefully and answer the questions below it. Life was not easy before Aryabhatta. Zero was not invented and also people could not multiply numbers. Thus mathematics had only 9 digits (1 to 9) and after that came 11 and so on. Find the answer to following operations in mathematics used then
What is 15+5 + 1+9 =?
Correct
Ans: c
Replace 10 by 11, 20 by 22 and so on.
15 +5 +1+9 actually 14 +5+ 1+9= 29
which is 32
Incorrect
Ans: c
Replace 10 by 11, 20 by 22 and so on.
15 +5 +1+9 actually 14 +5+ 1+9= 29
which is 32
-
Question 4 of 5
4. Question
Read the following information carefully and answer the questions below it. Rahul brought some sweets on his 21st birthday. He offered one less than the half of total number of sweets in the temple near the house. He also gave one sweet each to 3 beggars sitting on the stairs of ‘temple’. On the way back to home, he Stopped a big group of poor children and gave them halt of what was left with him. After reaching home he shared of the remaining two pieces of Sweets with his younger brother.
How many sweets did he originally had?
Correct
Ans: c
Let the number of sweets be x.
Number of sweets left with him after devoting
in Temple= x – [ (x/2)-1]=(x/2)+1
Number of sweets left with him after giving to the baggers = (x/2)-2
Number of sweets left with him after giving to the poor children = 1/2[(x/2)-2] = (x/4)-1
Number of sweets left with him after giving
to his brother = (x/4)-2 = 1
This gives x = 12
Incorrect
Ans: c
Let the number of sweets be x.
Number of sweets left with him after devoting
in Temple= x – [ (x/2)-1]=(x/2)+1
Number of sweets left with him after giving to the baggers = (x/2)-2
Number of sweets left with him after giving to the poor children = 1/2[(x/2)-2] = (x/4)-1
Number of sweets left with him after giving
to his brother = (x/4)-2 = 1
This gives x = 12
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Question 5 of 5
5. Question
Read the following information carefully and answer the questions below it. Rahul brought some sweets on his 21st birthday. He offered one less than the half of total number of sweets in the temple near the house. He also gave one sweet each to 3 beggars sitting on the stairs of ‘temple’. On the way back to home, he Stopped a big group of poor children and gave them halt of what was left with him. After reaching home he shared of the remaining two pieces of Sweets with his younger brother.
How many sweets did he offered in the temple?
Correct
Ans: c
Let the number of sweets be x.
Number of sweets left with him after devoting
in Temple= x – [ (x/2)-1]=(x/2)+1
Number of sweets left with him after giving to the baggers = (x/2)-2
Number of sweets left with him after giving to the poor children = 1/2[(x/2)-2] = (x/4)-1
Number of sweets left with him after giving
to his brother = (x/4)-2 = 1
This gives x = 12
Incorrect
Ans: c
Let the number of sweets be x.
Number of sweets left with him after devoting
in Temple= x – [ (x/2)-1]=(x/2)+1
Number of sweets left with him after giving to the baggers = (x/2)-2
Number of sweets left with him after giving to the poor children = 1/2[(x/2)-2] = (x/4)-1
Number of sweets left with him after giving
to his brother = (x/4)-2 = 1
This gives x = 12
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