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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
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Question 1 of 5
1. Question
300 g of salt solution has 40% salt in it. How much salt should be added to make it 50% in the solution?
Correct
Answer :b
40% is salt in 300 g of salt solution.
Then, quantity of salt = (40×300)/100 = 120 g
Now, by the condition in the question,
(120 +x)/(300+x)=50/100
(120+x)/(300+x)=1/2
240+2x=300+x
x=60 g
Incorrect
Answer :b
40% is salt in 300 g of salt solution.
Then, quantity of salt = (40×300)/100 = 120 g
Now, by the condition in the question,
(120 +x)/(300+x)=50/100
(120+x)/(300+x)=1/2
240+2x=300+x
x=60 g
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Question 2 of 5
2. Question
600g of sugar solution has 40% sugar in it. How much sugar should be added to make it 50% in the solution?
Correct
Answer :b
The existing solution contains 40%
sugar and here sugar has to be mixed.
Therefore, the other solution has 100% sugar.
According to the rule of alligation,
Required ratio = 50 : 10 = 5:1
The two mixtures should be added in the
ratio of 5: 1.
\Required sugar = (600/5)x1 = 120 g
Incorrect
Answer :b
The existing solution contains 40%
sugar and here sugar has to be mixed.
Therefore, the other solution has 100% sugar.
According to the rule of alligation,
Required ratio = 50 : 10 = 5:1
The two mixtures should be added in the
ratio of 5: 1.
\Required sugar = (600/5)x1 = 120 g
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Question 3 of 5
3. Question
A milk seller has a milk of Rs. 100 per litre. In what ratio should water be mixed in that milk, so that after selling the mixture at Rs. 80 per litre, he may get a profit of 50%?
Correct
Answer : a
Here, SP of milk = Rs. 80
and gain = 50%
∴ CP of milk = (100 x80)/150
[CP = ((100/(100 + gain%))x SP)]
=₹ 160/3 per litre
According to rule of allegation,
∴
Water : Milk = 140/3 : 160/3
=14 : 16 = 7: 8
Incorrect
Answer : a
Here, SP of milk = Rs. 80
and gain = 50%
∴ CP of milk = (100 x80)/150
[CP = ((100/(100 + gain%))x SP)]
=₹ 160/3 per litre
According to rule of allegation,
∴
Water : Milk = 140/3 : 160/3
=14 : 16 = 7: 8
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Question 4 of 5
4. Question
Out of 120 applications for a post, 70 are males and 80 have a driver’s license. What is the ratio between the minimum to maximum number of males having driver’s license ?
Correct
Answer : c
Since, there are 70 males out of 120 applicants, there must be 50 females.
For the minimum number of males to have a driver’s license all 50 females must have adriver’s license.
Thus, the number of males having a driver’s license, will be 80-50=30.
The Maximum possible number of males having a driver’s license is 70.
The ratio between the minimum and the maximum is 30 : 70 or 3: 7.
Incorrect
Answer : c
Since, there are 70 males out of 120 applicants, there must be 50 females.
For the minimum number of males to have a driver’s license all 50 females must have adriver’s license.
Thus, the number of males having a driver’s license, will be 80-50=30.
The Maximum possible number of males having a driver’s license is 70.
The ratio between the minimum and the maximum is 30 : 70 or 3: 7.
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Question 5 of 5
5. Question
In a certain examination, the number of those who passed was 4 times the number of those who failed. If there had been 35 fewer candidates and 9 more had failed, the ratio of passed and failed candidates would have been 2: 1, then the total number of candidates was
Correct
Answer : b
Let the number of failed and passed candidates be x and 4x, respectively.
Therefore, total number of candidates was
5x,
According to the question,
If total number of students had been5x – 35,
Then (4x-35-9)/(x+9) = 2/1
4x – 44 = 2 (x + 9)
4x – 2x = 18 + 44
2x = 62
x = 31
Thus, total number of candidates was 31 x 5
i.e., 155.
Incorrect
Answer : b
Let the number of failed and passed candidates be x and 4x, respectively.
Therefore, total number of candidates was
5x,
According to the question,
If total number of students had been5x – 35,
Then (4x-35-9)/(x+9) = 2/1
4x – 44 = 2 (x + 9)
4x – 2x = 18 + 44
2x = 62
x = 31
Thus, total number of candidates was 31 x 5
i.e., 155.
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