Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
The average salary per head of all employees of a company is Rs. 600. The average salary of 120 officers is Rs. 4000. If the average salary per head of the rest of the employees is560, find the total number of workers in the company.
Correct
Ans-b
From the figure it is clear that the ratio of the number of officers to the number of other employees would be 40:3400. Since there are 120 officers, there would be 3400 x 3 = 10200 workers in the company. Thus the total number of employees would be 10200 +120 = 10320.
Incorrect
Ans-b
From the figure it is clear that the ratio of the number of officers to the number of other employees would be 40:3400. Since there are 120 officers, there would be 3400 x 3 = 10200 workers in the company. Thus the total number of employees would be 10200 +120 = 10320.
-
Question 2 of 5
2. Question
A dishonest milkman purchased milk at Rs. 10 Per litre and mixed 5 1litres of water in it. By selling the mixture at the rate of Rs. 10 per litre he earns a profit of 25%. The quantity of the amount of the mixture that he had was:
Correct
Ans-c
The cost price of the mixture would have been Rs. 8 per litre for him to get a profit of 25% by selling at Rs. 10 per litre. The ratio of mixing would have been 1:4 (water is to milk) as can be seen in the figure:
Since we are putting in 5 litres of water, the amount of milk must be 20 litres. The amount of mixture then would become 25 litres.
Incorrect
Ans-c
The cost price of the mixture would have been Rs. 8 per litre for him to get a profit of 25% by selling at Rs. 10 per litre. The ratio of mixing would have been 1:4 (water is to milk) as can be seen in the figure:
Since we are putting in 5 litres of water, the amount of milk must be 20 litres. The amount of mixture then would become 25 litres.
-
Question 3 of 5
3. Question
A cistern contains 50 litres of water. 5 litres of water is taken out of it and replaced by wine. The process repeated again. Find the proportion of wine and water in the resulting mixture.
Correct
Ans-c
Amount of water left = 50 x 9/10 x 9/10= 40.5 litres. Hence, wine= 9.5 litres. Ratio of wine and
water = 19:81. Option (c) is correct.
Incorrect
Ans-c
Amount of water left = 50 x 9/10 x 9/10= 40.5 litres. Hence, wine= 9.5 litres. Ratio of wine and
water = 19:81. Option (c) is correct.
-
Question 4 of 5
4. Question
A container has a capacity of 20 gallons and is full of spirit. 4 gallons of spirit is drawn out and the container is again filed with water. This process is repeated 5 times. Find out how much spirit is left in the resulting mixture finally?
Correct
Ans-b
The amount of spirit left= 20 x 4/5 x 4/5 x 4/5 x 4/5 x 4/5 = 4096/625 = 6 (346/625).
Incorrect
Ans-b
The amount of spirit left= 20 x 4/5 x 4/5 x 4/5 x 4/5 x 4/5 = 4096/625 = 6 (346/625).
-
Question 5 of 5
5. Question
A vessel is full of refined oil. 1/4 of the refined oil is taken out and the vessel is filled with mustard oil. If the process is repeated 4 times and 10 litres of refined oil is finally left in the vessel, what is the capacity of the vessel?
Correct
Ans-c
Let the quantity of refined oil initially be O. Then we have Q x ¾ x ¾ x ¾ x ¾ = 10 → Q = 2560/81 litres.
Incorrect
Ans-c
Let the quantity of refined oil initially be O. Then we have Q x ¾ x ¾ x ¾ x ¾ = 10 → Q = 2560/81 litres.
Join our Official Telegram Channel HERE for Motivation and Fast Updates
Subscribe to our YouTube Channel HERE to watch Motivational and New analysis videos