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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The average height of 30 girls out of a class of 40 is 160 cm and that of the remaining girls is 156 cm. The average height of the whole class is
Correct
Ans-c
(30 x 160 + 10 x 156)/40 = 159.
Incorrect
Ans-c
(30 x 160 + 10 x 156)/40 = 159.
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Question 2 of 5
2. Question
The average weight of 6 persons is increased by 2.5 kg when one of them whose weight is 50 kg is replaced by a new man. The weight of the new man is
Correct
Ans-a
The total weight of the six people goes up by 15 kgs (when the average for 6 persons goes up by 2.5 kg). Thus, the new person must be 15 kgs more than the person who he replaces. Hence, the new person’s
weight = 50 + 15 = 65 kg.
Incorrect
Ans-a
The total weight of the six people goes up by 15 kgs (when the average for 6 persons goes up by 2.5 kg). Thus, the new person must be 15 kgs more than the person who he replaces. Hence, the new person’s
weight = 50 + 15 = 65 kg.
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Question 3 of 5
3. Question
The average age of three boys is 15 years. If their ages are in the ratio 3:5:7, the age of the youngest boy is
Correct
Ans-d
Total age = 3 x 15 = 45. Individual ages being in the ratio 3:5:7 their ages would be 9, 15 and 21 years respectively. The youngest boy would be 9 years.
Incorrect
Ans-d
Total age = 3 x 15 = 45. Individual ages being in the ratio 3:5:7 their ages would be 9, 15 and 21 years respectively. The youngest boy would be 9 years.
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Question 4 of 5
4. Question
The average of the first ten natural numbers is
Correct
Ans-b
Required average = (1 +2+3+……. +10)/10 =55/10 = 55 . Alternately you could use the formula for sum of the first n natural numbers as n (n + 1)/2 with n as 10, Then average = Sum/10= 10 x 11/2 x 10 = 5.5
Incorrect
Ans-b
Required average = (1 +2+3+……. +10)/10 =55/10 = 55 . Alternately you could use the formula for sum of the first n natural numbers as n (n + 1)/2 with n as 10, Then average = Sum/10= 10 x 11/2 x 10 = 5.5
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Question 5 of 5
5. Question
The average of the first ten whole numbers is
Correct
Ans-a
Required average (0 + 1+2+ +9)/10= 45/10 = 4.5
Incorrect
Ans-a
Required average (0 + 1+2+ +9)/10= 45/10 = 4.5
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