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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
How many natural numbers between 100 to 500 are multiples of 9?
Correct
Solution: A)
The series will be 108, 117, 126, ….495.
Hence, Answer = [(495-108)/9]+1 =44. Option (a) is correct.
Incorrect
Solution: A)
The series will be 108, 117, 126, ….495.
Hence, Answer = [(495-108)/9]+1 =44. Option (a) is correct.
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Question 2 of 5
2. Question
The sum of the first 20 terms of an AP whose first term and third term are 25 and 35, respectively is
Correct
Solution: d)
a = 25, a + 2d= 35 means d =5. The 20th term would be a + 19d= 25 +95 = 120. The sum of the series would be given by: sum-[20/2] x [25 + 120]= 1450. Option (d) is correct.
Incorrect
Solution: d)
a = 25, a + 2d= 35 means d =5. The 20th term would be a + 19d= 25 +95 = 120. The sum of the series would be given by: sum-[20/2] x [25 + 120]= 1450. Option (d) is correct.
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Question 3 of 5
3. Question
A number 39 is divided into three parts which are in A.P. and the sum of their squares is 515. Find the largest number.
Correct
Solution: b)
The three parts are 11, 13 and 15 since 112 + 132 +152 =515. Since, we want the largest number, the answer would be 15. Option (b) is correct.
Incorrect
Solution: b)
The three parts are 11, 13 and 15 since 112 + 132 +152 =515. Since, we want the largest number, the answer would be 15. Option (b) is correct.
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Question 4 of 5
4. Question
The 3rd and 8th term of a GP are 1/3 and 81, respectively. Find the 2nd
Correct
Solution: d)
3rd term ar2 = 1/3, 8th term ar7 =81
R5 = 243 Gives us: r =3
Hence, the second term will be given by (3rd term/r)=1/3
1/3 = 1/9. Option (d) is correct.
[Note: go forward in a G.P. you multiply by the common ratio, to go backward in a G.P. you divide by the common ratio.]
Incorrect
Solution: d)
3rd term ar2 = 1/3, 8th term ar7 =81
R5 = 243 Gives us: r =3
Hence, the second term will be given by (3rd term/r)=1/3
1/3 = 1/9. Option (d) is correct.
[Note: go forward in a G.P. you multiply by the common ratio, to go backward in a G.P. you divide by the common ratio.]
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Question 5 of 5
5. Question
The sum of 5 numbers in AP is 35 and the sum of their squares is 285. Which of the following is the third term?
Correct
Solution: b)
Since the sum of 5 numbers in AP is 35, their average would be 7. The average of 5 terms in an AP is also equal to the value of the 3rd term (logic of the middle term of an AP). Hence, the third term’s value would be 7. Option (b) is correct.
Incorrect
Solution: b)
Since the sum of 5 numbers in AP is 35, their average would be 7. The average of 5 terms in an AP is also equal to the value of the 3rd term (logic of the middle term of an AP). Hence, the third term’s value would be 7. Option (b) is correct.
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