Insta–DART (Daily Aptitude and Reasoning Test) 16 July 2021

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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Question 1 of 5

1. Question

The 6th and 20th terms of an AP are 8 and 20 respectively. Find the 30th term.

Correct

Answer : b

As we all know in AP series-

Nth term will be =a+(n-1)d,(where a-first term,n is total term,d is common difference),

6^{th} term will be -a+(6-1)d

a+ 5d= 8 and a+ 19d=-20. Solving we get 14d=-28→d=-2.

30^{th} term = 20th term + 10d =-20+10´ (-2) = -40. Option (b) is correct.

Incorrect

Answer : b

As we all know in AP series-

Nth term will be =a+(n-1)d,(where a-first term,n is total term,d is common difference),

6^{th} term will be -a+(6-1)d

a+ 5d= 8 and a+ 19d=-20. Solving we get 14d=-28→d=-2.

30^{th} term = 20th term + 10d =-20+10´ (-2) = -40. Option (b) is correct.

Question 2 of 5

2. Question

How many terms are there in the AP 10, 15, 30,…..120?

Correct

Answer : c

In order to count the number of terms in the AP, use the shortcut:

[{last term-first term)/common difference]+1.In this case it would become:

[(120-10)/5]+1=23. Option (c ) is correct.

Incorrect

Answer : c

In order to count the number of terms in the AP, use the shortcut:

[{last term-first term)/common difference]+1.In this case it would become:

[(120-10)/5]+1=23. Option (c ) is correct.

Question 3 of 5

3. Question

Find the number of terms of the series 1/27, 1/9, 1/3,….729

Correct

Answer : a

This is example of gp(geometric progression)series-

In this first term will be a,and common ratio will r,

So here u can find value of r=2^{nd} term/1^{st} term

=1/9/(1/27)

=3

Formula of nth term in gp=ar^n-1

729=1/27*(3)^n-1

R =3. 729 = 1/27(3)^{n-1},

(3)^9=(3)^n-1

n-1 =9 or n=10 option (a ) is correct

Incorrect

Answer : a

This is example of gp(geometric progression)series-

In this first term will be a,and common ratio will r,

So here u can find value of r=2^{nd} term/1^{st} term

=1/9/(1/27)

=3

Formula of nth term in gp=ar^n-1

729=1/27*(3)^n-1

R =3. 729 = 1/27(3)^{n-1},

(3)^9=(3)^n-1

n-1 =9 or n=10 option (a ) is correct

Question 4 of 5

4. Question

If the fifth term of a G.P. is 80 and first term is 5, what will be the 4th term of the G.P.?

Correct

Answer : c

6r^{4} = 80 →r^{4} = 80/5 ® r =2. Thus, 4^{th} term = ar^{3} = 5 (2)^{3} = 40. Option (c) is correct.

Incorrect

Answer : c

6r^{4} = 80 →r^{4} = 80/5 ® r =2. Thus, 4^{th} term = ar^{3} = 5 (2)^{3} = 40. Option (c) is correct.

Question 5 of 5

5. Question

Binay was appointed to Mindworkzz in the pay scale of 12000-1500-22,500. Find how many years he will take to reach the maximum of the scale.

Correct

Answer: a

12000 -1500-22500 means that the starting scale is 12000 and there is an increment of 1500 every year. Since, the total increment required to reach the top of his scale is 10500, the number of years required would be 10500/15 7. Option (a) is correct.

Incorrect

Answer: a

12000 -1500-22500 means that the starting scale is 12000 and there is an increment of 1500 every year. Since, the total increment required to reach the top of his scale is 10500, the number of years required would be 10500/15 7. Option (a) is correct.

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