Insta–DART (Daily Aptitude and Reasoning Test) 23 June 2021

Sol: (3)

Let us check the options one by one

Check for (1): M > N ≥ 0 < P

We can’t compare P and M. Hence, does not follow

Check for (2): M ≤ N < O = P

This leads to M < P. Hence, it does not follow.

Check for (3): M ≥ N = O > P

This leads to M > P means P < M. Hence it follows.

Check for (4): M ≥ N = O < P

We can’t compare P and M. Hence, it does not follow.

Sol: 4

Let us check all the options one by one.

Check for (1): I ≥ J = K > L ≤ M < N

I > L. And we can’t compare N and K. Hence, option 1) does not follow.

Check for (2): I ≥ J = K ≥ L ≤ M < N

This leads us to I ≥ L. Which means L ≤ I is true. But we can’t compare N and K. Hence, it does not follow.

Check for (3): I ≥ J = K ≤ L ≤ M < N

We can’t compare I and L. Hence, it does not follow.

Sol: (3)

Given expression:

A ≤ B = C > D ≥ E < F

We can’t compare A and D, and C and F. Hence, option 2) and 4) do not follow.

Again, B > E is true. Thus, option 3) follows but option 1) does not follow.

Sol: (4)

Check options one by one.

Check for (1): Priya < Rashi ≤ Sashi = Maya < Nikita = Kavita ≥ Lalit

This leads us to Nikita ≥ Lalit. Hence, does not follow.

Check for (2): Priya < Rashi ≤ Sashi = Maya ≤ Nikita = Kavita > Lalit

This leads to Nikita > Lalit. Hence, follows. But Rashi ≤ Nikita does not follow.

Check for (3): Priya < Rashi ≤ Sashi = Maya ≤ Nikita = Kavita ≥ Lalit

This leads us to Nikita ≥ Lalit and Rashi ≤ Nikita. Hence, does not follow.

Check for (4): Priya < Rashi ≤ Sashi = Maya < Nikita = Kavita > Lalit

This leads us to Nikita > Lalit and Rashi < Nikita. Hence, follows.

Sol: (4)

Check for (1): P ≤ Q ≤ R = S = T

Hence Q < T does not follow and P ≤ S means S ≥ P follows.

Check for (2): P < Q = R ≤ S < T

Hence, Q < T is true but S ≥ P does not follow.

Check for (3): P ≥ Q = R > S < T

We can’t compare Q and T.

Check for (4): P ≤ Q = R = S < T

This leads us to Q < T is true and P ≤ S or S ≥ P is true. Hence follows.