Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
Find the next number in the series 125, 80, 45, 20, ….
Correct
Answer: A) 5
Explanation:
The pattern is -45, -35, -25, -15. The next number = 20-15= 5Incorrect
Answer: A) 5
Explanation:
The pattern is -45, -35, -25, -15. The next number = 20-15= 5 -
Question 2 of 5
2. Question
A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and the other digits are correct, then the correct answer would be
Correct
Answer: C) 555681
Explanation:
987 = 3 * 7 * 47.
So, the required number must be divisible by each one of 3, 7, 47
553681 => (Sum of digits = 28, not divisible by 3)
555181 => (Sum of digits = 25, not divisible by 3)
555681 is divisible by each one of 3, 7, 47.Incorrect
Answer: C) 555681
Explanation:
987 = 3 * 7 * 47.
So, the required number must be divisible by each one of 3, 7, 47
553681 => (Sum of digits = 28, not divisible by 3)
555181 => (Sum of digits = 25, not divisible by 3)
555681 is divisible by each one of 3, 7, 47. -
Question 3 of 5
3. Question
What will be unit digit in 357 x 641 x 763?
Correct
Sol: c
357 = (34)14 x 3
So Unit digit in 357
= Unit digit in 1 x 3
= 3
641 = (64)10 x 6
So Unit digit in 641
= Unit digit in 6 x 6
= 6
763 = (74)15 x 73
So Unit digit in 761
= Unit digit in 1 x 343
= 3
So Unit digit in 357 x 641 x 763
= Unit digit in 3 x 6 x 3
= 4
We’ve used following formulae here:
Unit digit in 34 = 1
Unit digit in 64 = 6
Unit digit in 74 = 1
So Unit digit
– in ((3)4)n) will be 1.
– in ((6)4)n) will be 6.
– in ((7)4)n) will be 1.
Incorrect
Sol: c
357 = (34)14 x 3
So Unit digit in 357
= Unit digit in 1 x 3
= 3
641 = (64)10 x 6
So Unit digit in 641
= Unit digit in 6 x 6
= 6
763 = (74)15 x 73
So Unit digit in 761
= Unit digit in 1 x 343
= 3
So Unit digit in 357 x 641 x 763
= Unit digit in 3 x 6 x 3
= 4
We’ve used following formulae here:
Unit digit in 34 = 1
Unit digit in 64 = 6
Unit digit in 74 = 1
So Unit digit
– in ((3)4)n) will be 1.
– in ((6)4)n) will be 6.
– in ((7)4)n) will be 1.
-
Question 4 of 5
4. Question
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Correct
Sol. (a) 100 m
Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hrDistance covered in 6 minutes = (1/60) x 6 km = 1/10 km = 100 m
Therefore, Distance between the thief and policeman = (200 – 100) m = 100 m.
Incorrect
Sol. (a) 100 m
Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hrDistance covered in 6 minutes = (1/60) x 6 km = 1/10 km = 100 m
Therefore, Distance between the thief and policeman = (200 – 100) m = 100 m.
-
Question 5 of 5
5. Question
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Correct
Answer: Option C
Explanation:
Let speed of the car be x kmph.
Incorrect
Answer: Option C
Explanation:
Let speed of the car be x kmph.
Join our Official Telegram Channel HERE for Motivation and Fast Updates
Subscribe to our YouTube Channel HERE to watch Motivational and New analysis videos
