Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The letters from A to Z are numbered from 1 to 26 respectively. If GHI = 1578 and DEF = 912, then what is ABC equal to?
Correct
Answer : d
According to the question,
And
Similarly,
Hence, option (d) is correct.
Incorrect
Answer : d
According to the question,
And
Similarly,
Hence, option (d) is correct.
-
Question 2 of 5
2. Question
What is the missing term @ in the following?
ACPQ : BESU : : MNGI: @
Correct
Answer : d
As,
Hence, missing term @would be NPJM.
Incorrect
Answer : d
As,
Hence, missing term @would be NPJM.
-
Question 3 of 5
3. Question
Let A3BC and DE2F be four-digit numbers where each letter represents a different digit greater than 3. If the sum of the numbers is 15902, then what Is the difference between the values of A and D?
Correct
Answer : c
This can be solved by hit and trial method. The sum of C and F should be such that the unit digit should be 2. Let,
C+F = 8 + 4 =12
Hence, C = 8
And F = 4
Similarly, [(B +2) + 1] should have unit digit 0.
Let,
[(B+2) +(1)] = 10
↓
[carry from (C + F)]
Hence, B = 7
Similarly, (3+E) +1 should have unit digit 9, Let,
[(3+E) + 1] = 9
Hence, E = 5
Lastly, A and D should have sum equal to 15.
i.e A+ D = 15
or 6+9= 15
Now, A3BC + DE2F
= 6378 + 9524= 15902
So, difference between A and D
=9-6-3
Hence, correct option would be (c).
Incorrect
Answer : c
This can be solved by hit and trial method. The sum of C and F should be such that the unit digit should be 2. Let,
C+F = 8 + 4 =12
Hence, C = 8
And F = 4
Similarly, [(B +2) + 1] should have unit digit 0.
Let,
[(B+2) +(1)] = 10
↓
[carry from (C + F)]
Hence, B = 7
Similarly, (3+E) +1 should have unit digit 9, Let,
[(3+E) + 1] = 9
Hence, E = 5
Lastly, A and D should have sum equal to 15.
i.e A+ D = 15
or 6+9= 15
Now, A3BC + DE2F
= 6378 + 9524= 15902
So, difference between A and D
=9-6-3
Hence, correct option would be (c).
-
Question 4 of 5
4. Question
If every alternative letter of the English alphabet from B onwards (including B) is written in lower case (small letters) and the remaining letters are capitalised, then how is the first month of the second half of the year written?
Correct
Answer : d
The first month of the second half of the year is July which will be written as’ jUIY’.
Incorrect
Answer : d
The first month of the second half of the year is July which will be written as’ jUIY’.
-
Question 5 of 5
5. Question
If $ means ‘divided by’, @means ‘multiplied by’, # means ‘minus’, then the value of 10#5@1$5 is
Correct
Answer : d
According to the question,
10#5@1$5 = 10-5×1¸5
= 10 – 5* (1/5)
= 10 – 1 = 9
Incorrect
Answer : d
According to the question,
10#5@1$5 = 10-5×1¸5
= 10 – 5* (1/5)
= 10 – 1 = 9
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