Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
25 is divided into two parts. When we multiply the smaller part by 6 we get get the same thing when the bigger part is multiplied by 4 . The parts are :-
Correct
ANSWER : {C}
LET THE SMALL PART WILL BE {25-x}
HENCE, X*6 = {25-x}*4
6x = 100-4x
10x = 100
X = 10
Hence ,
BIGGER PART = 25 – x = 25-10 = 15
Incorrect
ANSWER : {C}
LET THE SMALL PART WILL BE {25-x}
HENCE, X*6 = {25-x}*4
6x = 100-4x
10x = 100
X = 10
Hence ,
BIGGER PART = 25 – x = 25-10 = 15
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Question 2 of 5
2. Question
1400 IS DIVIDED INTO 4 PARTS SUCH THAT TWICE THE FIRST PART , THRICE THE SECOND PART , 04 TIMES THE THIRD PART AND 12 TIMES THE LAST PART ARE ALL EQUAL. FIND THE FIRST PART :-
Correct
ANSWER : {C}
LET THE FOUR PART BE A ,B ,C & D . THEN ,
A+B+C+D = 1400 ——- (i)
2A = 3B = 4C = 12D ——— (ii)
A+B+C+D = 1400
A+ 2/3A + 2/4A + 2/12A = 1400
12A/12 + 8A/12 + 6A/12 + 2A/12 = 1400
28A/12 = 1400
A = 1400*12/28
A = 600
Incorrect
ANSWER : {C}
LET THE FOUR PART BE A ,B ,C & D . THEN ,
A+B+C+D = 1400 ——- (i)
2A = 3B = 4C = 12D ——— (ii)
A+B+C+D = 1400
A+ 2/3A + 2/4A + 2/12A = 1400
12A/12 + 8A/12 + 6A/12 + 2A/12 = 1400
28A/12 = 1400
A = 1400*12/28
A = 600
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Question 3 of 5
3. Question
THE PRICE OF A TABLE AND CHAIR ARE IN THE RATIO OF 25:6 . IF THE TABLE COSTS RS.950 MORE THAN THE CHAIR , THEN THE COST OF TWO CHAIRS IS :-
Correct
ANSWER : {D}
LET THE PRICES OF A TABLE AND A CHAIR BE 25x & 6x RUPEES RESPECTIVELY .
25x = 6x + 950
19x = 950
X= 950/19
= 50
HENCE , THE PRICE OF A CHAIR IS 6x = 6*50 = RS. 300
THE COST OF THE TWO CHAIRS = 2*RS.300 = RS. 600
Incorrect
ANSWER : {D}
LET THE PRICES OF A TABLE AND A CHAIR BE 25x & 6x RUPEES RESPECTIVELY .
25x = 6x + 950
19x = 950
X= 950/19
= 50
HENCE , THE PRICE OF A CHAIR IS 6x = 6*50 = RS. 300
THE COST OF THE TWO CHAIRS = 2*RS.300 = RS. 600
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Question 4 of 5
4. Question
IN A GROUP OF COWS AND HENS , THE NUMBER OF LEGS ARE 14 MORE THAN TWICE THE NUMBER OF HEADS. THE NUMBER OF COWS IN THE GROUP IS :-
Correct
ANSWER :- {A}
LET THE NUMBER OF COWS AND HENS BE ‘C’ AND ‘H’ RESPECTIVELY.
THE TOTAL NUMBER OF LEGS = 4C+2H
THE TOTAL NUMBER OF HEADS = C+H
4C+2H = 2 (C+H)+14
4C+2H=2C+2H+14
4C= 2C+14
2C = 14
C = 7
Incorrect
ANSWER :- {A}
LET THE NUMBER OF COWS AND HENS BE ‘C’ AND ‘H’ RESPECTIVELY.
THE TOTAL NUMBER OF LEGS = 4C+2H
THE TOTAL NUMBER OF HEADS = C+H
4C+2H = 2 (C+H)+14
4C+2H=2C+2H+14
4C= 2C+14
2C = 14
C = 7
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Question 5 of 5
5. Question
PERSON HAS RS.960 COMPRISING OF EQUAL NUMBER OF RS.50 , RS.20 AND RS.10 NOTES. HOW MANY NOTES OF EACH OF THE ABOVE IS AVAILABLE WITH HIM.
Correct
ANSWER:- {B}
LET THE NUMBER OF NOTES OF EACH DENOMINATION BE X .
THE TOTAL AMOUNT WILL BE
50x + 20x + 10x = RS.960
80x = 960
X = 960/80
X = 12
Incorrect
ANSWER:- {B}
LET THE NUMBER OF NOTES OF EACH DENOMINATION BE X .
THE TOTAL AMOUNT WILL BE
50x + 20x + 10x = RS.960
80x = 960
X = 960/80
X = 12
