Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
A journey of 192 km takes 2 hours less by a fast train than by a slow train. If the average speed or the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train’?
Correct
Answer : d
Solve this question using the values given in the options. Option (d) can be seen to fit the situation given by the problem as it gives us the following the following chain of thought: If the average speed of the faster train is 48 kmph, the average speed of the slower train would be 32 kmph. In this case, the time taken by the faster train (192/48 =4 hours) is 2 hours lesser than the time taken by the slower train (192/32 6 hours). This satisfies the condition given in the problem and hence
option (d) is correct.
Incorrect
Answer : d
Solve this question using the values given in the options. Option (d) can be seen to fit the situation given by the problem as it gives us the following the following chain of thought: If the average speed of the faster train is 48 kmph, the average speed of the slower train would be 32 kmph. In this case, the time taken by the faster train (192/48 =4 hours) is 2 hours lesser than the time taken by the slower train (192/32 6 hours). This satisfies the condition given in the problem and hence
option (d) is correct.
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Question 2 of 5
2. Question
A passenger train takes 2h less for a journey of 300 Kilometres if its speed is increased by 5 kmph over its usual speed. Find the usual speed.
Correct
Answer : d
The required speed s would be satisfying the equation
300/s -300/(s+2) = 5
Solving for s from the options it is clear that s 25.
Incorrect
Answer : d
The required speed s would be satisfying the equation
300/s -300/(s+2) = 5
Solving for s from the options it is clear that s 25.
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Question 3 of 5
3. Question
If Arun had walked 1 km/h faster, he would have taken 10 minutes less to walk 2 kilometre. What is Arun’s speed of walking?
Correct
Answer : c
Solve through options using trial and error. For usual speed 3 kmph we have:
Normal time → 2/3 hours= 40 minutes.
At 4 kmph the time would be 2/4 hrs, this gives
a distance of 10 minutes. Hence option (c) is correct.
Incorrect
Answer : c
Solve through options using trial and error. For usual speed 3 kmph we have:
Normal time → 2/3 hours= 40 minutes.
At 4 kmph the time would be 2/4 hrs, this gives
a distance of 10 minutes. Hence option (c) is correct.
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Question 4 of 5
4. Question
A plane left half an hour later than the scheduled time and in order to reach its destination 1500 kilometre away in time, it had to increase its speed by 33.33 per cent over its usual speed. Find its increased speed.
Correct
Answer : d
By increasing the speed by 33.33%, it would be able to reduce the time taken for travel by 25%. But since this is just able to overcome a time delay of 30 minutes, 30 minutes must be equivalent to 25% of the time originally taken. Hence, the original time must have been 2 hours and the original speed would be 750 kmph. Hence, the new speed would be 1000 kmph.
Incorrect
Answer : d
By increasing the speed by 33.33%, it would be able to reduce the time taken for travel by 25%. But since this is just able to overcome a time delay of 30 minutes, 30 minutes must be equivalent to 25% of the time originally taken. Hence, the original time must have been 2 hours and the original speed would be 750 kmph. Hence, the new speed would be 1000 kmph.
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Question 5 of 5
5. Question
A train moves at a constant speed of 120 km/h for one kilometre and at 40 kmph for the next one kilometre. What is the average speed of the train?
Correct
Answer : d
The average speed would be given by:
(120 x1x 40 x3)/4 = 60 kmph.
Incorrect
Answer : d
The average speed would be given by:
(120 x1x 40 x3)/4 = 60 kmph.