Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The average speed of a bus is three-fourth the average speed of a train. The train covers 240 km in 12 h. How much distance will the bus cover in 7 h?
Correct
Answer : c
Average speed of train = (240/12) = 20 km/h
Average speed of bus = (3/4) * 20 = 3 * 5 = 15 km/h
Required distance = 15 * 7 = 105 km
Incorrect
Answer : c
Average speed of train = (240/12) = 20 km/h
Average speed of bus = (3/4) * 20 = 3 * 5 = 15 km/h
Required distance = 15 * 7 = 105 km
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Question 2 of 5
2. Question
From stations M and N, two trains start moving towards each other at speed 125 km/h and 75 km/h, respectively. When the two trains meet each other, it is found that one train covers 50 km more than another. Find the distance between M and N.
Correct
Answer : b
Let the trains meet after time. t at a distance x from station N, then another train coming from station M covers a distance train (x + 50).
For station M, (x+ 50)= 125t
X= 125t- 50 …………………………….(1)
For station N, x= 75t ………………………………(2)
From Eqs. (1) and (2), we get
75t = 125t-50
t=1h
Distance between stations M and N
=125 + 75 t= 200 x 1= 200 km
Incorrect
Answer : b
Let the trains meet after time. t at a distance x from station N, then another train coming from station M covers a distance train (x + 50).
For station M, (x+ 50)= 125t
X= 125t- 50 …………………………….(1)
For station N, x= 75t ………………………………(2)
From Eqs. (1) and (2), we get
75t = 125t-50
t=1h
Distance between stations M and N
=125 + 75 t= 200 x 1= 200 km
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Question 3 of 5
3. Question
Two trains A and B start from Delhi and Patna towards Patna and Delhi, respectively. After passing each other, they take 16 h and 9 h to reach Patna and Delhi, respectively. If the train from Delhi is moving at 90 km/h, then find the speed of the other train (in km/h).
Correct
Answer : a
Given t1=16
T2=9 and speed (a)=90km/h
Speed of B will be=A speed *root t1/root t2
=90*4/3=120 km/h
Incorrect
Answer : a
Given t1=16
T2=9 and speed (a)=90km/h
Speed of B will be=A speed *root t1/root t2
=90*4/3=120 km/h
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Question 4 of 5
4. Question
Excluding stoppages, the speed of a train is 108 km/h and including stoppages, it is 90 km/h. For how many minutes does the train stop per hour?
Correct
Answer : c
Because of stoppages, train covers
18 km less per hour.
∴Time taken to cover 18 km
= (18/108)=(1/6)h = (1/6) * 60 = 10 min
Incorrect
Answer : c
Because of stoppages, train covers
18 km less per hour.
∴Time taken to cover 18 km
= (18/108)=(1/6)h = (1/6) * 60 = 10 min
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Question 5 of 5
5. Question
Without stoppages, the speed of a train is 150 km/h and with stoppages, it is 100 km/h. How many minutes, does the train stop?
Correct
Answer : a
Because of stoppages, train covers
50 km less per hour.
∴Time taken to cover 50 km
= (50/150) h = (50/150 ) * 60 = 20 min
Incorrect
Answer : a
Because of stoppages, train covers
50 km less per hour.
∴Time taken to cover 50 km
= (50/150) h = (50/150 ) * 60 = 20 min
