Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
In a game of 200 points, A can give 40 points to B and 56 points to C. How many points can B give to C ?
Correct
Answer : a
A: B = 200:160
A:C =200 144
∴ (B/C) = (B/A) * (A/C) = (160/200) * (200/144)
= (160/144) = (10/9) = (200/180)
Hence, B can give C 20 points.
Incorrect
Answer : a
A: B = 200:160
A:C =200 144
∴ (B/C) = (B/A) * (A/C) = (160/200) * (200/144)
= (160/144) = (10/9) = (200/180)
Hence, B can give C 20 points.
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Question 2 of 5
2. Question
In a game of 160 points, A can give 10 points to B and 30 points to C. How many points B can give C in a game of 60?
Correct
Answer : d
A:B=160:150, A: C = 160 : 130
(B/C) = [(B/A) * (A/C)] = [ (150/160) * (160/130)]
= (15/13) = (60/52) = 60 : 52
∴In a game of 60, B can give C = (60 – 52) = 8 points
Incorrect
Answer : d
A:B=160:150, A: C = 160 : 130
(B/C) = [(B/A) * (A/C)] = [ (150/160) * (160/130)]
= (15/13) = (60/52) = 60 : 52
∴In a game of 60, B can give C = (60 – 52) = 8 points
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Question 3 of 5
3. Question
In a 200 m race, A can beat B by 50 m and B can beat C by 8 m. In the same race, A can beat C by what distance?
Correct
Answer : c
According to the question,
A : B = 200 : 150
and B : C = 200 : 192
A : C = [(A/B) * (B/C)] = [ (200/150) * (200/192)] = (200/144)
So, A beats C by 9200 – 144) = 56 m
Incorrect
Answer : c
According to the question,
A : B = 200 : 150
and B : C = 200 : 192
A : C = [(A/B) * (B/C)] = [ (200/150) * (200/192)] = (200/144)
So, A beats C by 9200 – 144) = 56 m
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Question 4 of 5
4. Question
A, B and C are three contestants in a 500 m race. If A can give B a start of 20 m and A can give C a start of 32 m, how many metres start can B give to C?
Correct
Answer : c
Given that, a1 = 20m, a2 = 32 m and a3 = ?
According to the formula,
(L – a1) a3 = L ( a2 – a1)
(500 – 20 ) a3 = 500 ( 32 – 20)
480 a3 = 500 *12
a3 = (500 * 12)/480
∴a3 = (50/4) = 12.5 m
Hence, A can give C a start of 12.5 m.
Incorrect
Answer : c
Given that, a1 = 20m, a2 = 32 m and a3 = ?
According to the formula,
(L – a1) a3 = L ( a2 – a1)
(500 – 20 ) a3 = 500 ( 32 – 20)
480 a3 = 500 *12
a3 = (500 * 12)/480
∴a3 = (50/4) = 12.5 m
Hence, A can give C a start of 12.5 m.
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Question 5 of 5
5. Question
In a race of 600 m, A can beat B by 30 m and in a race of 500 m, B can beat C by 25 m. By how many metres will A beat C in a race of 400 m?
Correct
Answer : a
If A runs 600 m, then B runs 570 m
If A runs 400 m, B then runs
[(570/600)*400]m = 380 m
When B runs 500 m, then C runs 475 m
When B runs 380 m, then C runs
[(475/500) * 380] = 361 m
∴A beats C by (400 – 361) = 39 m
Incorrect
Answer : a
If A runs 600 m, then B runs 570 m
If A runs 400 m, B then runs
[(570/600)*400]m = 380 m
When B runs 500 m, then C runs 475 m
When B runs 380 m, then C runs
[(475/500) * 380] = 361 m
∴A beats C by (400 – 361) = 39 m
