Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Sambhu beats kalu by 30 meteres or 10 seconds.How much time was taken by sambhu to complete a race 1200 meters.
Correct
Ans :a
Kalu’s speed =3 m/s
For 1200 m ,kalu would take 400 seconds and sambhu would take 10 seconds less,hence 390 seconds.
Incorrect
Ans :a
Kalu’s speed =3 m/s
For 1200 m ,kalu would take 400 seconds and sambhu would take 10 seconds less,hence 390 seconds.
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Question 2 of 5
2. Question
What is the time taken by chandu to cover a distance of a distance of 360km by a motorcycle moving at a speed of 10m/s?
Correct
Ans-a
Since chandu is moving at a speed of 10m/s and he has to cover 360km or 360000 meteres ,the time taken would be given by 360000/10 seconds=36000 seconds=36000/60 minutes=600 minutes=10 hours.
Incorrect
Ans-a
Since chandu is moving at a speed of 10m/s and he has to cover 360km or 360000 meteres ,the time taken would be given by 360000/10 seconds=36000 seconds=36000/60 minutes=600 minutes=10 hours.
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Question 3 of 5
3. Question
Rajdhani express travels 650 km in 5 h and another 940km in 10 h,what is the average speed of train.
Correct
Ans-c
Total distance/Total time=1590/15=106kmph
Incorrect
Ans-c
Total distance/Total time=1590/15=106kmph
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Question 4 of 5
4. Question
Rishikant,during his journey ,travel for 20 minutes at a speed of 30km/h,another 30 min at a speed of 50km/h,and 1 hour at a speed of 50km/h and 1 hour at a speed of 60km/h.what is the average velocity.
Correct
ans-a
The distance covered in the various phases of his travel would be
10km +25km+50km+60km.
Thus the total distance covered =145 km in 2 hours 50 minutes
145km in 2.8333 hours
51.18kmph
Incorrect
ans-a
The distance covered in the various phases of his travel would be
10km +25km+50km+60km.
Thus the total distance covered =145 km in 2 hours 50 minutes
145km in 2.8333 hours
51.18kmph
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Question 5 of 5
5. Question
A motor car does a journey in 17.5 hours,covering the first half at 30km/h and the second half at 40 km/h.Find the distance of the journey.
Correct
Ans-b
If the car does half the journey @30 kmph and the other half at 40kmph its average speed can be estimated using weighted averages.
Since ,the distance travelled in each part of the journey is equal ,the ratio of time for which the car would travel would be inverse to the ratio of speeds .Since ,the speed ratio 3:4,the time ratio for the two halves of the journey would be 4:3.the average speed of the carwould be-
(30*4+40 *3)/7=240/7kmph.
It is further known that the car traveled for 17.5 hours(which is also equal to 35/2 hours)
Thus ,total distance=average speed *total time
=(240*35)/(2*7)
=120*5
=600km.
Incorrect
Ans-b
If the car does half the journey @30 kmph and the other half at 40kmph its average speed can be estimated using weighted averages.
Since ,the distance travelled in each part of the journey is equal ,the ratio of time for which the car would travel would be inverse to the ratio of speeds .Since ,the speed ratio 3:4,the time ratio for the two halves of the journey would be 4:3.the average speed of the carwould be-
(30*4+40 *3)/7=240/7kmph.
It is further known that the car traveled for 17.5 hours(which is also equal to 35/2 hours)
Thus ,total distance=average speed *total time
=(240*35)/(2*7)
=120*5
=600km.
