Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The sum of two numbers is 10. Their product is 20. Find the sum of the reciprocals of the two numbers.
Correct
Answer : c
Incorrect
Answer : c
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Question 2 of 5
2. Question
The difference between two numbers is 18. If four times the second number is less than three times the first number by 18, then what is the sum of these two numbers?
Correct
Answer : d
Let first number =x
and second number = y
According to the question,
x – y = 18 …………………(1)
and 3x – 4y = 18 ………………….(2)
On multiplying Eq. (1) by 3 and then
subtracting Eq. (ii) from it, we get
3x-3y 54
3x-4y = 18
y= 36
On putting the value of y in Eq. (1), we get
x = 18 + y = 18 + 36
x = 54
Required sum = x + y = 54+ 36= 90
Incorrect
Answer : d
Let first number =x
and second number = y
According to the question,
x – y = 18 …………………(1)
and 3x – 4y = 18 ………………….(2)
On multiplying Eq. (1) by 3 and then
subtracting Eq. (ii) from it, we get
3x-3y 54
3x-4y = 18
y= 36
On putting the value of y in Eq. (1), we get
x = 18 + y = 18 + 36
x = 54
Required sum = x + y = 54+ 36= 90
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Question 3 of 5
3. Question
The difference between a two-digit number and the number obtained by interchangıng the two digits of the number is 18. The sum of the two digits of the number is 12. What is the product of the digits of two-digit number?
Correct
Answer : a
Let the unit’s digit be y and ten’s digit be x.
Then, the number = 10x + y
When interchanging the place, the number is 10y + x.
According to the question,
(10x+ y) – (10y + x) = 18
10 x + y -10y – x = 18
9x – 9y=18
X – y = 2
and x+y = 12
On adding Eqs. (1) and (2), We get
x = 7
∴x = 7 and y = 5
Product = xy = 7 ´ 5 = 35
Incorrect
Answer : a
Let the unit’s digit be y and ten’s digit be x.
Then, the number = 10x + y
When interchanging the place, the number is 10y + x.
According to the question,
(10x+ y) – (10y + x) = 18
10 x + y -10y – x = 18
9x – 9y=18
X – y = 2
and x+y = 12
On adding Eqs. (1) and (2), We get
x = 7
∴x = 7 and y = 5
Product = xy = 7 ´ 5 = 35
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Question 4 of 5
4. Question
On Children’s Day, sweets were to be distributed amongst equally 300 children. But on that particular day 50 children remained absent; hence each child got one extra sweet. How many Sweets were distributed?
Correct
Answer: c
Let total number of sweets = x
According to the question,
(x / 250) – ( x /300) = 1
(6x – 5x ) /1500 = 1
∴x = 1500
∴Required number of sweets = 1500
Incorrect
Answer: c
Let total number of sweets = x
According to the question,
(x / 250) – ( x /300) = 1
(6x – 5x ) /1500 = 1
∴x = 1500
∴Required number of sweets = 1500
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Question 5 of 5
5. Question
There are two examination halls P and Q. If 10 students shifted P to Q , then the number of students will be equal in both the examination halls. If 20 students shifted from Q to P, then the students of P would be doubled to the students of Q . The numbers of students would be in P and Q, respectively are
Correct
Answer : d
Let number of students in examination
halls P and Q is x and y respectively.
Then, as per the first condition,
x-10= y + 10
x-y= 20 …………………………………………..(1)
As per the second condition,
x+ 20 = 2(y- 20)
x+20 = 2y-40
x-2y= -60 ……………………………………………..(2)
On subtracting Eq. (2) from Eq. (1), we get
-y+ 2y= 20+60
y= 80
Putting the value of y in Eq. (1). we get
x-80=20
x= 100
Hence, number of students in examination
halls P and Q is 100 and 80, respectivelym
Incorrect
Answer : d
Let number of students in examination
halls P and Q is x and y respectively.
Then, as per the first condition,
x-10= y + 10
x-y= 20 …………………………………………..(1)
As per the second condition,
x+ 20 = 2(y- 20)
x+20 = 2y-40
x-2y= -60 ……………………………………………..(2)
On subtracting Eq. (2) from Eq. (1), we get
-y+ 2y= 20+60
y= 80
Putting the value of y in Eq. (1). we get
x-80=20
x= 100
Hence, number of students in examination
halls P and Q is 100 and 80, respectivelym
