Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The present ages of two persons are 36 and 50 yr, respectively. If after n yr the ratio of their ages will be 3: 4, then the value of n is
Correct
Answer : d
According to the question,
(36+n)/(50+n) = (3/4)
144 + 4n = 150 + 3n
∴n = 6
Incorrect
Answer : d
According to the question,
(36+n)/(50+n) = (3/4)
144 + 4n = 150 + 3n
∴n = 6
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Question 2 of 5
2. Question
The ratio of the ages of Ram and Rahim 10 yr ago was 1:3. The ratio of their ages five years hence will be 2:3. Then, the ratio of their present ages is
Correct
Answer : b
Let 10 yr ago, ages of Ram and Rahim
were x yr and 3x yr, respectively
Then, present age of Ram= (x+ 10)
and present age of Rahim = (3x + 10)
According to the question,
[(x+10+5)/(3x+10+5)] = (2/3)
3x + 45 = 6x + 30
3x=15
∴x = 5
Hence, required ratio = (5+10)/(3*5+10)
= (15/25) = 3:5
Incorrect
Answer : b
Let 10 yr ago, ages of Ram and Rahim
were x yr and 3x yr, respectively
Then, present age of Ram= (x+ 10)
and present age of Rahim = (3x + 10)
According to the question,
[(x+10+5)/(3x+10+5)] = (2/3)
3x + 45 = 6x + 30
3x=15
∴x = 5
Hence, required ratio = (5+10)/(3*5+10)
= (15/25) = 3:5
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Question 3 of 5
3. Question
At present, Palash is three times Arnav’s age. After 7 yr, Palash will be twice Arnav s age, then how many times will Palash’s age be in another 14 yr time with respect to Arnav’s age then?
Correct
Answer : a
Let Arnav’s age = x yr
Then, Palash’s age = 3x yr
According to the question,
3x + 7 = 2(x +7)
3x +7 = 2x +14
X = 7
∴age of Arnav after 14 yr = 7+ 14 = 21 yr
and Palash’s present age = 21 yr
Hence,
Palash’s age is one time of Arnav’s age.
Incorrect
Answer : a
Let Arnav’s age = x yr
Then, Palash’s age = 3x yr
According to the question,
3x + 7 = 2(x +7)
3x +7 = 2x +14
X = 7
∴age of Arnav after 14 yr = 7+ 14 = 21 yr
and Palash’s present age = 21 yr
Hence,
Palash’s age is one time of Arnav’s age.
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Question 4 of 5
4. Question
10 yr before, the ratio of ages of A and B was 13:17. After 17 yr from now, the ratio of their ages will be 10:11 The present age of B is
Correct
Answer : c
Let the ages of A and B 10 yr before
were 13x yr and 17x yr, respectivelyY
Then, present age of A= 13x + 10
and present age of B = 17x + 10
According to the question,
∴[(13x+10+17)/17x+10+17)]=(10/11)
[(13x + 27)/(17x+27)] =(10/11)
143x+ 297= 170x + 270
27x= 27
X= 1
Hence, present age of B =17×1+10
=27 yr
Incorrect
Answer : c
Let the ages of A and B 10 yr before
were 13x yr and 17x yr, respectivelyY
Then, present age of A= 13x + 10
and present age of B = 17x + 10
According to the question,
∴[(13x+10+17)/17x+10+17)]=(10/11)
[(13x + 27)/(17x+27)] =(10/11)
143x+ 297= 170x + 270
27x= 27
X= 1
Hence, present age of B =17×1+10
=27 yr
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Question 5 of 5
5. Question
3 yr before, the average age of a family of 5 members was 17 yr. Due to birth of a new child, the average age is same today. The present age of child is
Correct
Answer : d
3yr before,
Total age of 5 members
=17 x5 = 85 yr
∴The present age of all members of family
85+3 x5 =100 yr
Let the age of child be x yr.
∴Present average age of family including
the child
=(100+x)/6
17 = (100+x)/6
∴x = 102 – 100 = 2 yr
Incorrect
Answer : d
3yr before,
Total age of 5 members
=17 x5 = 85 yr
∴The present age of all members of family
85+3 x5 =100 yr
Let the age of child be x yr.
∴Present average age of family including
the child
=(100+x)/6
17 = (100+x)/6
∴x = 102 – 100 = 2 yr
