Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
For a certain sum, the simple interest in 2 yr at 8% per annum is Rs.110 more than the simple interest in 1 yr at the rate of 5% per annum for the same sum. Find the sum.
Correct
Answer : b
Given, SI1 –SI2 =110, T1 =2yr,
T2 =1 yr, R1 =8%, R2 = 5%
According to the question,
[(P*8*2)/100]-[(P*5*1)/100]=110
= (11P/100) = 110
P = Rs. 1000
Incorrect
Answer : b
Given, SI1 –SI2 =110, T1 =2yr,
T2 =1 yr, R1 =8%, R2 = 5%
According to the question,
[(P*8*2)/100]-[(P*5*1)/100]=110
= (11P/100) = 110
P = Rs. 1000
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Question 2 of 5
2. Question
A sum was lent out for a certain time. The sum amounts to Rs. 400 at 10% annual interest rate. when the sum was lent out at 4% annual interest rate, it amount t0 Rs. 200. Find the sum.
Correct
Answer : a
According to the question,
[P+(P*10*T)/100]-[P+(P*4*T)/100]
=400-200
[(6PT)/100] = 200
PT = [(200*100)/6 = 10000/3
Again, for 10% rate,
SI = (P´10´T)/100 = [[(10000/3)/3]*10]/100 = (1000/3)
∴Sum (P) = 400-(1000/3) = (1200-1000)/3
=Rs. (200/3)
Incorrect
Answer : a
According to the question,
[P+(P*10*T)/100]-[P+(P*4*T)/100]
=400-200
[(6PT)/100] = 200
PT = [(200*100)/6 = 10000/3
Again, for 10% rate,
SI = (P´10´T)/100 = [[(10000/3)/3]*10]/100 = (1000/3)
∴Sum (P) = 400-(1000/3) = (1200-1000)/3
=Rs. (200/3)
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Question 3 of 5
3. Question
A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then Rs.56 more would have been obtained. What is the sum?
Correct
Answer : b
According to the question,
[P*(R+2)*4/100] – [(P*R*4)/100] = 56
[(4PR+8P-4PR)/100]=56
(8P/100)=56
P=(56´100)/8=Rs. 700
Incorrect
Answer : b
According to the question,
[P*(R+2)*4/100] – [(P*R*4)/100] = 56
[(4PR+8P-4PR)/100]=56
(8P/100)=56
P=(56´100)/8=Rs. 700
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Question 4 of 5
4. Question
The simple interest on a certain sum of money for 2(1/2) yr at 12% per annum is Rs. 20 less than the simple interest on the same sum for 3(1/2) yr at 10% per annum. Find the sum.
Correct
Answer : d
Given, T1 = (5/2), R1 = 12%, T2 = (7/2) yr
And R2 = 10%
Let the sum be P.
Then, [(P*10*7)/(100*2) ] – [(P*12*5)/(100*2)] = 20
(7P/20) – (3P/10 ) = 20
∴P = 20 ´20 = Rs. 400
Incorrect
Answer : d
Given, T1 = (5/2), R1 = 12%, T2 = (7/2) yr
And R2 = 10%
Let the sum be P.
Then, [(P*10*7)/(100*2) ] – [(P*12*5)/(100*2)] = 20
(7P/20) – (3P/10 ) = 20
∴P = 20 ´20 = Rs. 400
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Question 5 of 5
5. Question
At what rate per annum will the simple interest on a certain sum of money be (1/5) of the amount in 10 yr?
Correct
Answer : b
Let sum = P, then SI = (P/5), time = 10yr
∴Rate = [(100*P)/(P*5*10)] = 2%
Incorrect
Answer : b
Let sum = P, then SI = (P/5), time = 10yr
∴Rate = [(100*P)/(P*5*10)] = 2%
