Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Deepak invested an amount of Rs. 21250 for 6yr. At what rate of simple interest, will he obtain the total amount of Rs. 26350 at the end of 6 yr.
Correct
Answer : d
SI = 26350 – 21250 = Rs. 5100
∴Rate = [(SI *100)/Principal*Time)]
=[(5100*100)/(21250*6)]=4%
Incorrect
Answer : d
SI = 26350 – 21250 = Rs. 5100
∴Rate = [(SI *100)/Principal*Time)]
=[(5100*100)/(21250*6)]=4%
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Question 2 of 5
2. Question
The difference of simple interest from two banks for Rs. 1000 in 2 yr is Rs. 20. Find the difference in rates of interest.
Correct
Answer : c
Let the two rates be R1 AND R2.
According to the question.
[[(1000*2*R1)/100] – [(1000*2*R2)/100]] = 20
(2000(R1-R2)/100 = 20
∴(R1 – R2)=20/20 =1%
Incorrect
Answer : c
Let the two rates be R1 AND R2.
According to the question.
[[(1000*2*R1)/100] – [(1000*2*R2)/100]] = 20
(2000(R1-R2)/100 = 20
∴(R1 – R2)=20/20 =1%
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Question 3 of 5
3. Question
Raju lent Rs. 400 to Ajay for 2yr and Rs. 100 to Manoj for 4 yr and received from both Rs. 60 as collective interest. Find the rate of interest, simple interest being calculated.
Correct
Answer : a
According to the question,
[(R*400*2)/100] +[(R*100*4)/100] = 60
12R = 60
R = (60/12) = 5%
Incorrect
Answer : a
According to the question,
[(R*400*2)/100] +[(R*100*4)/100] = 60
12R = 60
R = (60/12) = 5%
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Question 4 of 5
4. Question
2/3 part of my sum is lent out at 3%, 1/6 part is lent out at 6% and remaining part is lent out at 12%. All the three parts are lent out at simple interest. If the annual income is Rs. 25, what is the sum?
Correct
Answer : a
Let entire sum = P
According to the question,
(2/3)P *3%+(1/6)P*6% + [1-((2/3)+(1/6))]P*12%
(2P/3)*(3/100)+(P/6)*(6/100)+[1-(4+1)/6](12P/100) = 25
(2P/100) +(P/100)+(2P/100) =25
5P = 2500, P=500
Incorrect
Answer : a
Let entire sum = P
According to the question,
(2/3)P *3%+(1/6)P*6% + [1-((2/3)+(1/6))]P*12%
(2P/3)*(3/100)+(P/6)*(6/100)+[1-(4+1)/6](12P/100) = 25
(2P/100) +(P/100)+(2P/100) =25
5P = 2500, P=500
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Question 5 of 5
5. Question
A sum of Rs. 1521 is lent out in two parts in such a way that the interest on one part at 10% for 5 yr is equal to that of another part at 8% for 10 yr. What will be the two parts of sum?
Correct
Answeer : d
Given, T1 = 5 yr, R1 = 10% and T2 = 10yr and R2 = 8%
Let the first part = x
Then, second part =(1521-x)
((9x)*5*10)/100 = [ (1521 – x )*10*8]/100
5x = 12168 – 8x
13x = 12168
X = Rs. 936
And second parts = 1521 – 936 = Rs. 585
Incorrect
Answeer : d
Given, T1 = 5 yr, R1 = 10% and T2 = 10yr and R2 = 8%
Let the first part = x
Then, second part =(1521-x)
((9x)*5*10)/100 = [ (1521 – x )*10*8]/100
5x = 12168 – 8x
13x = 12168
X = Rs. 936
And second parts = 1521 – 936 = Rs. 585
