Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Charu purchased a dinner set at 3/10 th of its selling price and sold it at 10% more than its CP. Find the gain per cent.
Correct
Answer : d
Let SP = Rs. 100
∴CP = (3/10)*100 = Rs. 30
New SP = 30 * (110/100) = Rs. 33
Gain = 33 – 30 = Rs. 3
∴Gain % = (3/30) * 100% = (300/30)% = 10%
Incorrect
Answer : d
Let SP = Rs. 100
∴CP = (3/10)*100 = Rs. 30
New SP = 30 * (110/100) = Rs. 33
Gain = 33 – 30 = Rs. 3
∴Gain % = (3/30) * 100% = (300/30)% = 10%
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Question 2 of 5
2. Question
The owner of a furniture shop charges his customer 18% more than the CP. If a customer paid Rs. 10207 for a dining table, then find its original price.
Correct
Answer : b
Original CP = [100/(100+Gain%)]*SP
= (100/118)*10207 = Rs. 8650
Incorrect
Answer : b
Original CP = [100/(100+Gain%)]*SP
= (100/118)*10207 = Rs. 8650
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Question 3 of 5
3. Question
Meena purchased two fans each at Rs. 1200. She sold one fan at the loss of 5% and other at the gain of 10%. Find total gain or loss per cent.
Correct
Answer : c
Total CP = 2* 1200 = Rs. 2400
SP at 5% loss = (9/100)*1200 = Rs. 1140
SP at 10% gain = (110/100)*1200
= Rs. 1320
Total SP = 1140 + 1320 = Rs. 2460
∴Gain = 2460 – 2400 = Rs. 60
∴Gain % = (60/2400)´100% = 2.5%
Incorrect
Answer : c
Total CP = 2* 1200 = Rs. 2400
SP at 5% loss = (9/100)*1200 = Rs. 1140
SP at 10% gain = (110/100)*1200
= Rs. 1320
Total SP = 1140 + 1320 = Rs. 2460
∴Gain = 2460 – 2400 = Rs. 60
∴Gain % = (60/2400)´100% = 2.5%
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Question 4 of 5
4. Question
A woman bought eggs at 30 per dozen. The selling price per hundred so as to gain 12% will be (in Rs. )
Correct
Answer : a
12 eggs cost = Rs. 30
Then, cost price of 1 egg = (30/12) = Rs. 2.5
∴Cost price of 100 eggs = 2.5 ´100 = Rs.250
Now, let the SP of 100 eggs be Rs. X
Then, [(SP – CP)/CP ]/100 = Profit %
[(x-250)/250 ]´100 = 12
[(x – 250 )/5] ´ 2 = 12
X – 250 = (12´5)/2 = 12
X – 250 = (12´5)/2 = 30
X = 250 + 30 = Rs. 280
Incorrect
Answer : a
12 eggs cost = Rs. 30
Then, cost price of 1 egg = (30/12) = Rs. 2.5
∴Cost price of 100 eggs = 2.5 ´100 = Rs.250
Now, let the SP of 100 eggs be Rs. X
Then, [(SP – CP)/CP ]/100 = Profit %
[(x-250)/250 ]´100 = 12
[(x – 250 )/5] ´ 2 = 12
X – 250 = (12´5)/2 = 12
X – 250 = (12´5)/2 = 30
X = 250 + 30 = Rs. 280
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Question 5 of 5
5. Question
A man purchases a certain number of oranges at 4 a rupee and the same number of oranges at 5 a rupee. He mixes them together and sells them at 4 a rupee. What is his gain or loss per cent?
Correct
Answer : c
CP of 1 orange for 1st rate = Rs. 1/4
CP of 1 orange for 2nd rate =Rs. 1/5
CP of 2 oranges after mixing = (1/4) +(1/5) = Rs. 9/20
CP of I orange after mixing = [9/(20*2)] = Rs. 9/40
SP of 1 orange after mixing = Rs. 1/4
∴Gain = (1/4) – (9/40) = Rs. 1/40
∴Gain % = [(1/40)*(40/9)´100]%
= (100/9)% = 11(1/9)%
Incorrect
Answer : c
CP of 1 orange for 1st rate = Rs. 1/4
CP of 1 orange for 2nd rate =Rs. 1/5
CP of 2 oranges after mixing = (1/4) +(1/5) = Rs. 9/20
CP of I orange after mixing = [9/(20*2)] = Rs. 9/40
SP of 1 orange after mixing = Rs. 1/4
∴Gain = (1/4) – (9/40) = Rs. 1/40
∴Gain % = [(1/40)*(40/9)´100]%
= (100/9)% = 11(1/9)%
