Insta–DART (Daily Aptitude and Reasoning Test) 14 January 2021
Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
In an office, 40% of the staff is female.40% of the female and 60% of the male voted for me. The percentage of votes I got was
Correct
Answer : d
Let total number of staff be 100.
Female staff = 40
Male staff = (100 – 40) = 60
Votes cast by females = (40/100) * 40 = 16
Votes cast by males = (60/100)*60 = 36
Votes cast by both (males + females) = 16 + 36 = 52
∴Percentage votes obtained = 52%
Incorrect
Answer : d
Let total number of staff be 100.
Female staff = 40
Male staff = (100 – 40) = 60
Votes cast by females = (40/100) * 40 = 16
Votes cast by males = (60/100)*60 = 36
Votes cast by both (males + females) = 16 + 36 = 52
∴Percentage votes obtained = 52%
Question 2 of 5
2. Question
Ram sells his goods 25% cheaper than Shyam and 25% dearer than Hari. How much percentage is Hari’s goods cheaper than Shyan?
Correct
Answer : c
Let selling price of goods by Shyam be Rs. 100
∴ Selling price of goods by Ram=Rs. 75
125% of selling price of goods by Hari = 75
Selling price of goods by Hari = (100/125)*75 = Rs. 60
So, Hari’s goods are cheaper than Shyam’s
goods by (40/100)*100% = 40%
Incorrect
Answer : c
Let selling price of goods by Shyam be Rs. 100
∴ Selling price of goods by Ram=Rs. 75
125% of selling price of goods by Hari = 75
Selling price of goods by Hari = (100/125)*75 = Rs. 60
So, Hari’s goods are cheaper than Shyam’s
goods by (40/100)*100% = 40%
Question 3 of 5
3. Question
The ratio of the number of boys and girls in a school is 3: 2. If 20% of the boys and 25% of the girls are scholarship holders, then the percentage of the students who do not get the scholarship, is
Correct
Answer : a
Let number of boys be 300.
Number of girls 200
Boys holding scholarship = (20/100)*300 = 60
Girls holding scholarship = (25/100)*200 = 50
Total students holding scholarship
= 60 + 50 = 110
\Percentage of students not holding
Scholarship = [(500-110)/500]*100%
=(390/500)*100% = 78%
Incorrect
Answer : a
Let number of boys be 300.
Number of girls 200
Boys holding scholarship = (20/100)*300 = 60
Girls holding scholarship = (25/100)*200 = 50
Total students holding scholarship
= 60 + 50 = 110
\Percentage of students not holding
Scholarship = [(500-110)/500]*100%
=(390/500)*100% = 78%
Question 4 of 5
4. Question
A reduction of 20% in the price of wheat enables a person to buy 3.5 kg more wheat for Rs. 770. The original price of rice is
Correct
Answer : a
Let original price be x.
New price per kg = [80/100 * (x )] = Rs. [(4x)/5]
According to the question,
[770/(4x/5)] – [770/x] = 3.5
(3850/4x)-(770/x) =7/2
(3850 – 3080) = 14x
14x = 770
∴X = (770/14) = Rs.55
∴Original price of the wheat is 55 per kg.
Incorrect
Answer : a
Let original price be x.
New price per kg = [80/100 * (x )] = Rs. [(4x)/5]
According to the question,
[770/(4x/5)] – [770/x] = 3.5
(3850/4x)-(770/x) =7/2
(3850 – 3080) = 14x
14x = 770
∴X = (770/14) = Rs.55
∴Original price of the wheat is 55 per kg.
Question 5 of 5
5. Question
Fresh grapes contain 80% water, while dry grapes contain 10% water. If the weight of dry grapes is 500 kg, then what is its total weight when it is fresh?
Correct
Answer : d
Let the weight of fresh grapes be x.
Quantity of water in it = (80/100) *x = (4x/5)
Quantity of pulp in it = [(x – (4x/5) ] = x/5
Quantity of water in 500 kg dry grapes = (10/100)´500 = 50 kg
∴ Quantity of pulp in it = (500-50) = 450kg
(x/5 )= 450
∴X = 2250 kg
Incorrect
Answer : d
Let the weight of fresh grapes be x.
Quantity of water in it = (80/100) *x = (4x/5)
Quantity of pulp in it = [(x – (4x/5) ] = x/5
Quantity of water in 500 kg dry grapes = (10/100)´500 = 50 kg
∴ Quantity of pulp in it = (500-50) = 450kg
(x/5 )= 450
∴X = 2250 kg
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