Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
An alloy of gold and silver weights 50g. It contains 80% gold. How much gold should be added to the alloy, so that percentage of gold is increased to 90?
Correct
Answer : a
Gold in 50g of alloy = 80 * (50/100) = 40 g
Let x g gold must be added
Now, according to the question,
(40+x)/(50+x) = 90/100
100 (40 + x) = 90 (50 + x)
10 (40 + x) =9 (50 + x)
400 + 10x = 450 + 9x
x = 450 – 400 = x = 50 g
Thus, 50 g of gold must be added to make
it 90%.
Incorrect
Answer : a
Gold in 50g of alloy = 80 * (50/100) = 40 g
Let x g gold must be added
Now, according to the question,
(40+x)/(50+x) = 90/100
100 (40 + x) = 90 (50 + x)
10 (40 + x) =9 (50 + x)
400 + 10x = 450 + 9x
x = 450 – 400 = x = 50 g
Thus, 50 g of gold must be added to make
it 90%.
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Question 2 of 5
2. Question
Veena spends 25% of her monthly on household expenses. Her income annual income is 4.32 lakh. What is the total amount that Veena spends on household expenses in 8 months together?
Correct
Answer : d
Annual household expenses
= Rs. (25% of 4.32 *105 )
= Rs. [(25/100)*4.32*105]
=Rs. (25*4.32*103)
∴ Household expenses for 8 months
= Rs. [(25*4.32/12)*8*103] = Rs. 72000
Incorrect
Answer : d
Annual household expenses
= Rs. (25% of 4.32 *105 )
= Rs. [(25/100)*4.32*105]
=Rs. (25*4.32*103)
∴ Household expenses for 8 months
= Rs. [(25*4.32/12)*8*103] = Rs. 72000
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Question 3 of 5
3. Question
The salary of an employee of a company increases every month by 4%. If his salary in August was 6300, then what would be his approximate salary in month of October of the same year?
Correct
Answer : c
Required salary in October = [ 6300*(104/100)*(104/100)]
=(63*104*1.04)
= Rs. 6814.08 = Rs. 6814
Incorrect
Answer : c
Required salary in October = [ 6300*(104/100)*(104/100)]
=(63*104*1.04)
= Rs. 6814.08 = Rs. 6814
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Question 4 of 5
4. Question
1 L of water is added to 5 L of alcohol and water solution containing 40% alcohol strength. The strength of alcohol in the new solution will be
Correct
Answer : b
Quantity of alcohol in 5 L of solution
= (40/100 )*5 = 2L
Quantity of alcohol in 6 L of solution = 2 L
∴ Strength of alcohol in new solution
=[(2/6)*100)% = 33(1/3)%
Incorrect
Answer : b
Quantity of alcohol in 5 L of solution
= (40/100 )*5 = 2L
Quantity of alcohol in 6 L of solution = 2 L
∴ Strength of alcohol in new solution
=[(2/6)*100)% = 33(1/3)%
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Question 5 of 5
5. Question
In an examination, 49% students failed in English, 36% students failed in Hindi, while 15% failed in both. If total number of passed students is 450, then how many students did appear in the examination?
Correct
Answer : d
According to the formula,
Percentage of students passed in both the
subjects
= [100 – (x + y – z)]%
= (100 – (49 + 36 – 15)]% = 30%
Let total number of students = x
According to the question,
x *(30/100) = 450
x = (450/30)*100
=1500
∴ Total number of students = 1500
Incorrect
Answer : d
According to the formula,
Percentage of students passed in both the
subjects
= [100 – (x + y – z)]%
= (100 – (49 + 36 – 15)]% = 30%
Let total number of students = x
According to the question,
x *(30/100) = 450
x = (450/30)*100
=1500
∴ Total number of students = 1500
