Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
A contractor employs 200 men to build a bund. They finish 5/6 of the work in 10 weeks. Then rain sets in and not only does the work remain suspended for 4 weeks but also half of the work already done is washed away. After the rain, when the work is resumed, only 140 men turn up. The total time in which the contractor is able to complete the work assuming that there are no further disruptions in the schedule is
Correct
Answer : c
2000 man weeks before the rain, 5/6th of the work is completed. Hence, 2400 men weeks will be the total amount of work. However, due to the rain halt the work gets washed off → This means that 1000 man weeks worth of work must have got washed off. This leaves 1400 men weeks of work to be completed by the 140 men. They will take 10 more weeks and hence the total time required is 24 weeks.
Incorrect
Answer : c
2000 man weeks before the rain, 5/6th of the work is completed. Hence, 2400 men weeks will be the total amount of work. However, due to the rain halt the work gets washed off → This means that 1000 man weeks worth of work must have got washed off. This leaves 1400 men weeks of work to be completed by the 140 men. They will take 10 more weeks and hence the total time required is 24 weeks.
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Question 2 of 5
2. Question
In a journey of 48 km performed by tonga, rickshaw and cycle in that order, the distance covered by the three ways in that order are in the ratio of 8:1:3 and charges per kilometre in that order are in the ratio of 8:1:4. If the tonga charges being 24 paise per kilometre, the total cost of the journey is
Correct
Answer : a
Total distances covered under each mode = 32, 4
and 12 km respectively.
Total charges = 32 × 24 + 4 × 3 + 12 x 12 = 924 paise.
= Rs. 9.24
Incorrect
Answer : a
Total distances covered under each mode = 32, 4
and 12 km respectively.
Total charges = 32 × 24 + 4 × 3 + 12 x 12 = 924 paise.
= Rs. 9.24
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Question 3 of 5
3. Question
A bag contains 25 paise, 50 paise and 1 Re. coins. There are 220 coins in all and the total amount in the bag is Rs. 160. If there are thrice as many 1 Re. coins as there are 25 paise coins, then what is the number of 50 paise coins?
Correct
Answer : b
The no. of coins of 1 Re = 3x and 25p = x.
Conventionally, we can solve this using equations as follows.
A + B + C = 220
A = 3C
A + 0.5B + 0.25C = 160
We have a situation with 3 equations and 3 un-
knowns. and we can solve for
A (no. of 1 Re coins),
B (no. of 50 paise coins) and
C (no. of 25 paise coins)
However, a much smarter approach would be to go
through the options. If we check option (a)- number
of 50 paise coins = 60 we would get the number of
1 Re coins as 120 and the number of 25 paise coins
as 40.
Incorrect
Answer : b
The no. of coins of 1 Re = 3x and 25p = x.
Conventionally, we can solve this using equations as follows.
A + B + C = 220
A = 3C
A + 0.5B + 0.25C = 160
We have a situation with 3 equations and 3 un-
knowns. and we can solve for
A (no. of 1 Re coins),
B (no. of 50 paise coins) and
C (no. of 25 paise coins)
However, a much smarter approach would be to go
through the options. If we check option (a)- number
of 50 paise coins = 60 we would get the number of
1 Re coins as 120 and the number of 25 paise coins
as 40.
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Question 4 of 5
4. Question
Which of the following will have the maximum change in their values if 5 is added to both the numerator and denominator of all the fractions?
Correct
Answer : b
2/3 becomes 7/8 a change from 0.666 to 0.875 while the other changes are smaller than this. For instance 4/7 becomes 9/12 a change from 0.5714 to 0.75 which is smaller than the change in 2/3. Similarly, the other options can be checked and rejected.
Incorrect
Answer : b
2/3 becomes 7/8 a change from 0.666 to 0.875 while the other changes are smaller than this. For instance 4/7 becomes 9/12 a change from 0.5714 to 0.75 which is smaller than the change in 2/3. Similarly, the other options can be checked and rejected.
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Question 5 of 5
5. Question
40 men could have finished the whole project in 28 days but due to the inclusion of a few more men, work got done in 3/4 of the time. Find out how many more men were included (in whole numbers).
Correct
Answer : c
Since, the work gets done in 25% less time there
must have been an addition of 33.33% men.
This would mean 13.33 men extra → which would
mean 14 extra men (in whole numbers)
Incorrect
Answer : c
Since, the work gets done in 25% less time there
must have been an addition of 33.33% men.
This would mean 13.33 men extra → which would
mean 14 extra men (in whole numbers)
