Insta–DART (Daily Aptitude and Reasoning Test) 30 December 2020

Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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Question 1 of 5

1. Question

In a factory, the ratio of the numbers of employees of three types A, B and C is 9: 13 :18 and their wages are in the ratio of 10: 7 :4. If number of employees of type C is 54 and wages of every employee of type B is Rs. 1400, then find the total wages of all the employees of type A.

Correct

Answer : b

Given ratio of employees = 9 13:18

Let number of A’s employees 9x

Number of B’s employees = 13x

and number of C’s employees = 18x

According to the question,

18x = 54

∴x = 3

∴Number of employees of type A

= 9 x 3 = 27

Similarly, Wages of every employee of type A = (10/7)´1400 = 2000

Required wages = 27 x 2000 = Rs.54000

Incorrect

Answer : b

Given ratio of employees = 9 13:18

Let number of A’s employees 9x

Number of B’s employees = 13x

and number of C’s employees = 18x

According to the question,

18x = 54

∴x = 3

∴Number of employees of type A

= 9 x 3 = 27

Similarly, Wages of every employee of type A = (10/7)´1400 = 2000

Required wages = 27 x 2000 = Rs.54000

Question 2 of 5

2. Question

Number of employees in a factory decreases in the ratio of 8 : 7 and salary of employees increases in the ratio of 5:6. Find wheather the total salary given to the employees is increased or decreased and in what ratio?

Correct

Answer : d

Let total number of employees in

beginning = 8 K and total number of

employees in present = 7K

of employees in

Let salary of an employee in beginning = 5l

and salary of an employee in present = 6l

∴Total salary in beginning

= 8K x 5l = 40 Kl

and total salary in present

= 7K x 6l = 42Kl

Required ratio = 40 KI : 42 KI = 20: 21

Clearly, salary is increased.

Incorrect

Answer : d

Let total number of employees in

beginning = 8 K and total number of

employees in present = 7K

of employees in

Let salary of an employee in beginning = 5l

and salary of an employee in present = 6l

∴Total salary in beginning

= 8K x 5l = 40 Kl

and total salary in present

= 7K x 6l = 42Kl

Required ratio = 40 KI : 42 KI = 20: 21

Clearly, salary is increased.

Question 3 of 5

3. Question

Out of 120 applications for a post, 70 are males and 80 have a driver’s license. What is the ratio between the minimum to maximum number of males having driver’s license ?

Correct

Answer : c

Since, there are 70 males out of 120 applicants, there must be 50 females.

For the minimum number of males to have a driver’s license all 50 females must have a driver’s license.

Thus, the number of males having a driver’s license, will be 80-50=30.

The Maximum possible number of males having a driver’s license is 70.

The ratio between the minimum and the maximum is 30 : 70 or 3: 7.

Incorrect

Answer : c

Since, there are 70 males out of 120 applicants, there must be 50 females.

For the minimum number of males to have a driver’s license all 50 females must have a driver’s license.

Thus, the number of males having a driver’s license, will be 80-50=30.

The Maximum possible number of males having a driver’s license is 70.

The ratio between the minimum and the maximum is 30 : 70 or 3: 7.

Question 4 of 5

4. Question

In a certain examination, the number of those who passed was 4 times the number of those who failed. If there had been 35 fewer candidates and 9 more had failed, the ratio of passed and failed candidates would have been 2: 1, then the total number of candidates was

Correct

Answer : b

Let the number of failed and passed

candidates be x and 4x, respectively.

Therefore, total number of candidates was

5x.

According to the question,

If total number of students had been5x – 35,

Then (4x-35-9)/(x+9) = 2/1

4x – 44 = 2 (x + 9)

4x – 2x = 18 + 44

2x = 62

x = 31

Thus, total number of candidates was 31 x 5

i.e., 155.

Incorrect

Answer : b

Let the number of failed and passed

candidates be x and 4x, respectively.

Therefore, total number of candidates was

5x.

According to the question,

If total number of students had been5x – 35,

Then (4x-35-9)/(x+9) = 2/1

4x – 44 = 2 (x + 9)

4x – 2x = 18 + 44

2x = 62

x = 31

Thus, total number of candidates was 31 x 5

i.e., 155.

Question 5 of 5

5. Question

Rs. 710 were divided among A, B and C in such a way that A had Rs. 40 more than B and C had Rs. 30 more than A. How much was C’s share?

Correct

Answer : a

Let B gets x.

Then, A gets (x + 40) and C gets (x + 70).

According to the question,

x + 40 + x + x + 70 = 710

3x = 710 – 110 = 600

X = 600/3 = 200

∴C’s share = 200 + 70 = Rs.270

Incorrect

Answer : a

Let B gets x.

Then, A gets (x + 40) and C gets (x + 70).

According to the question,

x + 40 + x + x + 70 = 710

3x = 710 – 110 = 600

X = 600/3 = 200

∴C’s share = 200 + 70 = Rs.270

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