Insta–DART (Daily Aptitude and Reasoning Test) 28 December 2020
Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Out of two sections A and B, 10 students of section B shift to A, as a result strength of A becomes 3 times the strength of B. But, if 10 students shift over from A to B, both A and B become equal in strength. Ratio of the number of students in section A that of section B is
Correct
Answer : a
A + 10 = 3 (B- 10)
A – 3B = – 20 ………………( 1 )
And (A – 10) = (B + 10)
A – B = 20 ……………. ( 2 )
On subtracting Eq. (2) from Eq. (1), we get
A – 3B – A + B = – 20 – 20
– 2B = – 40
B = 20
Now, by using Eq. (ii),
A = 20 + 20 = 40.
: Ratio of the numbers of students of A and
B = 40 : 20 = 2:1
Incorrect
Answer : a
A + 10 = 3 (B- 10)
A – 3B = – 20 ………………( 1 )
And (A – 10) = (B + 10)
A – B = 20 ……………. ( 2 )
On subtracting Eq. (2) from Eq. (1), we get
A – 3B – A + B = – 20 – 20
– 2B = – 40
B = 20
Now, by using Eq. (ii),
A = 20 + 20 = 40.
: Ratio of the numbers of students of A and
B = 40 : 20 = 2:1
Question 2 of 5
2. Question
A sum of money is to be divided equally among P, Q and R in the respective ratio of 5: 6:7 and another sum of money is to be divided between S and T equally. If S got Rs. 2100 less than P, then how much amount did Q receive?
Correct
Answer : d
Couldn’t be determined, since the total amount of money is not given in either of the case.
Incorrect
Answer : d
Couldn’t be determined, since the total amount of money is not given in either of the case.
Question 3 of 5
3. Question
Nandita scores 80% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit,
where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 89 marks in Sanskrit, 98 marks in Mathematics and 81 marks in English?
Correct
Answer : a
Total of maximum marks of all subjects
= 105 x 5 = 525
80% of 525 = ( 525 ´ 80 )/ 100 = 420
Obtained marks of four subjects (Hindi,
Sanskrit, Mathematics and English)
= 89 + 92 + 98+81 = 360
So, the obtained marks in Science
= 420 – 360 = 60
Incorrect
Answer : a
Total of maximum marks of all subjects
= 105 x 5 = 525
80% of 525 = ( 525 ´ 80 )/ 100 = 420
Obtained marks of four subjects (Hindi,
Sanskrit, Mathematics and English)
= 89 + 92 + 98+81 = 360
So, the obtained marks in Science
= 420 – 360 = 60
Question 4 of 5
4. Question
Rs.2186 are distributed among A, B and C. If money given to them is decreased by Rs. 26, Rs. 28 and Rs. 32 respectively, then they have money in the ratio of 9: 13: 8. What is the amount given to A?
Correct
Answer : c
Amount given to A = 9K + 26
Amount given to B = 13K + 28
and amount given to C = 8K + 32
According to the question,
(9K + 26) + (13K + 28) + (8K + 32)
= 2186
30K + 86 = 2186
30K = 2100
\K = 70
Hence, amount given to A = 9K + 26
= 9 x 70 + 26
= 630 + 26 = Rs. 656
Incorrect
Answer : c
Amount given to A = 9K + 26
Amount given to B = 13K + 28
and amount given to C = 8K + 32
According to the question,
(9K + 26) + (13K + 28) + (8K + 32)
= 2186
30K + 86 = 2186
30K = 2100
\K = 70
Hence, amount given to A = 9K + 26
= 9 x 70 + 26
= 630 + 26 = Rs. 656
Question 5 of 5
5. Question
A person gave 2/5 part of his income to his elder son and 30% part to his younger son. He saved his remaining money in three trusts A, B and C in the ratio of 3:5:2. If difference between the amoun got by his both sons is 2000, how much amount he saved in trust C?
Correct
Answer : c
Let the person have Rs.x.
Then, share of elder son = Rs. 2x/5
and share of younger son = Rs. 3x/10
Acccrding to the question,
(2x/5) – (3x/10 )= 2000
x/10 = 2000
x = 20000
Remaining amount saved in trusts
Incorrect
Answer : c
Let the person have Rs.x.
Then, share of elder son = Rs. 2x/5
and share of younger son = Rs. 3x/10
Acccrding to the question,
(2x/5) – (3x/10 )= 2000
x/10 = 2000
x = 20000
Remaining amount saved in trusts
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