Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The average of two numbers is 62. If 2 is added to the number, the ratio between the numbers becomes 1: 2. The smaller number is
Correct
Answer : d
Let the numbers be x and y, x ˂ y
Then, x + y = 124;
(X + 2)/y = ½
∴y = 2x + 4
Solving above equations, we get
Y = 84, x = 40
Incorrect
Answer : d
Let the numbers be x and y, x ˂ y
Then, x + y = 124;
(X + 2)/y = ½
∴y = 2x + 4
Solving above equations, we get
Y = 84, x = 40
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Question 2 of 5
2. Question
The average daily wages of A, B and C is Rs. 120. If B earns Rs. 40 more than C per day and A earns double of what C earns per day, the wages A per day is
Correct
Answer : c
Let daily wages of C = x
Then, daily wages of A = 2x
And, daily wages of B = x + 40
Hence, average daily wages of A, B and C = (x + 2x + x + 40 )/3 = ( 4x + 40 )/3
∴( 4x + 40 )/3 = 120 or, 4x + 40 = 360
4x = 320 or, x = 80
∴Wages of A per day = 2 ´ 80 = Rs. 160.
Incorrect
Answer : c
Let daily wages of C = x
Then, daily wages of A = 2x
And, daily wages of B = x + 40
Hence, average daily wages of A, B and C = (x + 2x + x + 40 )/3 = ( 4x + 40 )/3
∴( 4x + 40 )/3 = 120 or, 4x + 40 = 360
4x = 320 or, x = 80
∴Wages of A per day = 2 ´ 80 = Rs. 160.
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Question 3 of 5
3. Question
With an average speed of 40 km/hr a train reaches its destination on time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. The total journey is
Correct
Answer : c
Let the distance be x km
Then it is given that (x/35) – (x/40) = 15/60
Or 5x/ (35 x40 ) = 1/4
Or x = ( 35×40 ) / 5 ´ 4 = 70
Incorrect
Answer : c
Let the distance be x km
Then it is given that (x/35) – (x/40) = 15/60
Or 5x/ (35 x40 ) = 1/4
Or x = ( 35×40 ) / 5 ´ 4 = 70
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Question 4 of 5
4. Question
In a competitive examination, the average marks obtained was 45. It was later discovered that there was 45, It was later discovered that there was some error in computerization and the marks of 90 candidates had to be changed from 80 to 50 and the average came down to 40 marks. The total no. of candidates who appeared in examination is
Correct
Answer : c
Let the number of candidates be x , Then, total marks obtained by all the candidates = 45x
Marks reduced for 90 candidates = 30 ´ 90 = 2700
Total reduced marks = 45x – 2700
Reduced average = ( 45x – 2700 )/ x
∴40 = ( 45x – 2700 )/ x
Or, 40x = 45x – 2700
5x = 2700 or, x = 540
Incorrect
Answer : c
Let the number of candidates be x , Then, total marks obtained by all the candidates = 45x
Marks reduced for 90 candidates = 30 ´ 90 = 2700
Total reduced marks = 45x – 2700
Reduced average = ( 45x – 2700 )/ x
∴40 = ( 45x – 2700 )/ x
Or, 40x = 45x – 2700
5x = 2700 or, x = 540
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Question 5 of 5
5. Question
A man whose bowling average is 12.4 takes 5 wickets for 26 runs and thereby decreases his average by 0.4. The number of wickets, taken by before his last match is
Correct
Answer : a
Let the number of wickets taken before the last match = x
Total run scored after last match = 12.4x + 26
After last match average is reduced by 0.4 runs
So it become 12
Then total run scored = Average ´ Number of wickets taken
= 12 ´ (x + 5 )
12.4x + 26 = 12x + 60
0.4x + 26 = 12x + 60
0.4x = 34
X = 85
Incorrect
Answer : a
Let the number of wickets taken before the last match = x
Total run scored after last match = 12.4x + 26
After last match average is reduced by 0.4 runs
So it become 12
Then total run scored = Average ´ Number of wickets taken
= 12 ´ (x + 5 )
12.4x + 26 = 12x + 60
0.4x + 26 = 12x + 60
0.4x = 34
X = 85
