Insta–DART (Daily Aptitude and Reasoning Test) 22 December 2020

Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21

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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.

Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).

Wish you all the best ! 🙂

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Question 1 of 5

1. Question

A cricketer has a certain average for 10 innings. In the eleventh innings, he scored 216 runs, there by increasing his average by 12 runs. Find out his new average.

Correct

Answer : a

Let average after 10^{th} innings = x

According to the question,

10x + 216 = 11 ( x + 12 )

X = 216 – 132 = 84

∴New average = 84 + 12 = 96

Incorrect

Answer : a

Let average after 10^{th} innings = x

According to the question,

10x + 216 = 11 ( x + 12 )

X = 216 – 132 = 84

∴New average = 84 + 12 = 96

Question 2 of 5

2. Question

A cricketer whose bowling average is 12.4 runs per wicket, takes 5 wickets for 26 runs and there by decreases his average by 0.4. Find out the number of wickets taken by him till the last match.

Correct

Answer : c

Let x be the number of wickets taken till the last match.

According to the question ,

( 12.4 x + 26 ) = 12( x + 5 )

12.4x + 26 = 12 x + 60

0.4 x = 34

∴X = ( 34 / 0.4 ) = 85

Incorrect

Answer : c

Let x be the number of wickets taken till the last match.

According to the question ,

( 12.4 x + 26 ) = 12( x + 5 )

12.4x + 26 = 12 x + 60

0.4 x = 34

∴X = ( 34 / 0.4 ) = 85

Question 3 of 5

3. Question

Nine friends have a dinner in a hotel. Eight of them spent Rs. 12 each on their meals and the ninth spent Rs. 16 more than the average expenditure of all the nine. Find out the total money spent by them.

Correct

Answer : a

Let average expenditure of 9 persons = x .

According to the question,

12 ´ 8 + ( x + 16 ) = 9x

8x = 112

∴x = ( 112/8) = 14

∴Total money spent = 9x = 9 ´ 14 = Rs. 126

Incorrect

Answer : a

Let average expenditure of 9 persons = x .

According to the question,

12 ´ 8 + ( x + 16 ) = 9x

8x = 112

∴x = ( 112/8) = 14

∴Total money spent = 9x = 9 ´ 14 = Rs. 126

Question 4 of 5

4. Question

The average weight of the students in four sections A, B, C and D is 60 kg. The average weight of the students of A, B, C and D individually are 45 kg, 50 kg, 72 kg and 80 kg, respectively. If the average weight of the students of section A and B together is 48 kg and that of B and C together is 60 kg, what is the ratio of the number of students in sections A and D?

Correct

Answer : b

Let number of students in the sections A, B, C and D be a, b, c and d, respectively. Then, total weight of students of section A = 45a

Total weight of students of section B = 50b

Total weight of students of section C = 72c

Total weight of students of section D = 80d

According to the question,

Average weight of students of sections A and B = 48kg

∴ [( 45a + 50 b) / ( a+b )] = 48

45a + 50b = 48a + 48b

3a = 2b

15a = 10b

And average weight of students of sections

B and C = 60kg

50b + 72c = 60( b + c )

10b = 12c

Now, average weight of students of A, B, C and D = 60 kg

∴45a + 50b + 72c + 80d

= 60 ( a + b + c + d )

15a + 10b – 12c – 20d = 0

15a = 20d

a:d = 4:3

Incorrect

Answer : b

Let number of students in the sections A, B, C and D be a, b, c and d, respectively. Then, total weight of students of section A = 45a

Total weight of students of section B = 50b

Total weight of students of section C = 72c

Total weight of students of section D = 80d

According to the question,

Average weight of students of sections A and B = 48kg

∴ [( 45a + 50 b) / ( a+b )] = 48

45a + 50b = 48a + 48b

3a = 2b

15a = 10b

And average weight of students of sections

B and C = 60kg

50b + 72c = 60( b + c )

10b = 12c

Now, average weight of students of A, B, C and D = 60 kg

∴45a + 50b + 72c + 80d

= 60 ( a + b + c + d )

15a + 10b – 12c – 20d = 0

15a = 20d

a:d = 4:3

Question 5 of 5

5. Question

The average age of students of a class is 15.8 yr. The average age of boys in the class is 16.4 yr and that of the girls is 15.4 yr. Find out the ratio of the number of boys to the number of girls in the class.

Correct

Answer : c

Clearly, Boys : Girls = 0.4 : 0.6 = 2:3

Incorrect

Answer : c

Clearly, Boys : Girls = 0.4 : 0.6 = 2:3

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