Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
In a cricket match, the run rate was 3.2 in the first 10 overs. To reach the target 282,how much should be the run rate in the remaining 40 overs?
Correct
The number of runs scored in the first 10 overs = 10 X 3.2=32
Remaining overs = 50 – 10 = 40 overs
Remaining runs ( required ) = 282 – 32 = 250 overs
∴The run rate in the remaining 40 overs = (250/40) = 6.25
∴Ans. a) 6.25
Incorrect
The number of runs scored in the first 10 overs = 10 X 3.2=32
Remaining overs = 50 – 10 = 40 overs
Remaining runs ( required ) = 282 – 32 = 250 overs
∴The run rate in the remaining 40 overs = (250/40) = 6.25
∴Ans. a) 6.25
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Question 2 of 5
2. Question
The average weight of 16 boys in a class in 50.25 kg. The average weight of the remaining 8 boy is 45.15 Kg. What is the average weight of all the boys in the class?
Correct
The total weight of 16 boys = 16 x50.25 = 804 kg
The total weight o0f 8 boys = (Total weight of all the boys / Total number of boys)
= [(804 + 361.2) / (16 + 8)]
= (1165.2 / 24)
= 48.55
Ans. a) 48.55 Kg
Incorrect
The total weight of 16 boys = 16 x50.25 = 804 kg
The total weight o0f 8 boys = (Total weight of all the boys / Total number of boys)
= [(804 + 361.2) / (16 + 8)]
= (1165.2 / 24)
= 48.55
Ans. a) 48.55 Kg
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Question 3 of 5
3. Question
A batsman has a certain average after 9 innings. By scoring 100 runs in his 10th innings he observed that his average increasing by 8 runs. Find his new average.
Correct
Let his average score after 9 innings be ‘ x ‘.
Total score in 9 innings = 9x.
Average score of 10 innings = ( 9x + 100 )/10
∴(9x + 100 /10) = x + 8
9x + 100 = 10x + 80
20 = x
∴His new average = x + 8 = 20 + 8 = 28
∴Ans. c) 28
Incorrect
Let his average score after 9 innings be ‘ x ‘.
Total score in 9 innings = 9x.
Average score of 10 innings = ( 9x + 100 )/10
∴(9x + 100 /10) = x + 8
9x + 100 = 10x + 80
20 = x
∴His new average = x + 8 = 20 + 8 = 28
∴Ans. c) 28
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Question 4 of 5
4. Question
Sumitra has scored 56% marks in the first 7 exams. How much should she score in the 8th exam to get overall average score of 60%?
Correct
Sumitra’s total score in the first 7 exams = 7 x 56 = 392
(392 + Her score in the 8th exam)/ 8 = 60
∴The required score in the 8th exam = 60 x8 – 392
= 480 – 392
= 88
∴Ans. a) 88%
Incorrect
Sumitra’s total score in the first 7 exams = 7 x 56 = 392
(392 + Her score in the 8th exam)/ 8 = 60
∴The required score in the 8th exam = 60 x8 – 392
= 480 – 392
= 88
∴Ans. a) 88%
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Question 5 of 5
5. Question
The average weight of 100 students is 46 kg. The average weight of boys is 50 kg and, that of girls is 40. How many boys are there?
Correct
Let the number of boys and girls be B and G.
B + G = 100;
G = 100 -B
Total weight of 100 students = 46 × 100 = 4600
Total weight of boys = 50 × B = 50 B
Total weight of girls = 40 × G = 40 G
∴ 50 B + 40 G = 4600
50 B + 40 (100 – B) = 4600
10 B = 4600 – 4000
10 B = 600
B = 600/10 = 60
∴ Ans. c) 60
Incorrect
Let the number of boys and girls be B and G.
B + G = 100;
G = 100 -B
Total weight of 100 students = 46 × 100 = 4600
Total weight of boys = 50 × B = 50 B
Total weight of girls = 40 × G = 40 G
∴ 50 B + 40 G = 4600
50 B + 40 (100 – B) = 4600
10 B = 4600 – 4000
10 B = 600
B = 600/10 = 60
∴ Ans. c) 60
