Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
A sum of money is to be divided equally among P, Q and R in the respective ratio of 5 : 6 : 7 and another sum of money is to be divided between S and T equally. If S got Rs. 2100 less than P, then how much amount did Q receive?
Correct
Answer : d
Couldn’t be determined, since the total amount of money is not given in either of the case.
Incorrect
Answer : d
Couldn’t be determined, since the total amount of money is not given in either of the case.
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Question 2 of 5
2. Question
Nandita scores 80 % marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 89 marks in hindi, 92 marks in Sanskrit, 98 marks in Mathematics and 81 marks in English?
Correct
Answer : a
Total of maximum marks of all subjects = 105 x 5 = 525
80 % of 525 = 525×80/ 100= 420
Obtained marks of four subjects ( Hindi, Sanskrit, Mathematics and English )
= 89 + 92 + 98 + 81 = 360
So, the obtained marks in Science = 420 – 360 = 60
Incorrect
Answer : a
Total of maximum marks of all subjects = 105 x 5 = 525
80 % of 525 = 525×80/ 100= 420
Obtained marks of four subjects ( Hindi, Sanskrit, Mathematics and English )
= 89 + 92 + 98 + 81 = 360
So, the obtained marks in Science = 420 – 360 = 60
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Question 3 of 5
3. Question
In a factory, the ratio of the numbers of employees of three types A, B and C is 9 : 13 : 18 and their wages are in the ratio of 10 : 7 : 4 . If number of employees of type C is 54 and wages of every employee of type B is Rs. 1400, then find the total wages of all the employees of type A.
Correct
Answer : b
Given ratio of employees = 9 : 13 : 18
Let number of A’s employees = 9x
Number of B’s employees = 13x
And number of C’s employees = 18x
According to the question, 18x = 54
X = 3
\Number of employees of type A = 9x 3 = 27
Similarly, Wages of every employee of type A = 10/7 x 1400 = Rs 2000
Required wages = 27 x2000 = Rs. 54000
Incorrect
Answer : b
Given ratio of employees = 9 : 13 : 18
Let number of A’s employees = 9x
Number of B’s employees = 13x
And number of C’s employees = 18x
According to the question, 18x = 54
X = 3
\Number of employees of type A = 9x 3 = 27
Similarly, Wages of every employee of type A = 10/7 x 1400 = Rs 2000
Required wages = 27 x2000 = Rs. 54000
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Question 4 of 5
4. Question
Number of employees in a factory decreases in the ratio of 8 : 7 and salary of employees increases in the ratio of 5 : 6 . Find weather the total salary given to the employees is increased or decreased and in what ratio ?
Correct
Answer : d
Let total number of employees in beginning = 8k and total number of employees in present = 7k
Let salary of an employee in beginning = 5 l
And salary of an employee in present = 6 l
\ Total salary in beginning = 8k x 5 l = 40kl
And total salary in present = 7k x 6l = 42kl
Required ratio = 40kl : 42kl = 20 : 21
Clearly, salary is increased.
Incorrect
Answer : d
Let total number of employees in beginning = 8k and total number of employees in present = 7k
Let salary of an employee in beginning = 5 l
And salary of an employee in present = 6 l
\ Total salary in beginning = 8k x 5 l = 40kl
And total salary in present = 7k x 6l = 42kl
Required ratio = 40kl : 42kl = 20 : 21
Clearly, salary is increased.
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Question 5 of 5
5. Question
Out of 120 applications for a post, 70 are males and 80 have a driver’s license. What is the ratio between the minimum to maximum number of males having driver’s license ?
Correct
Answer : c
Since, there are 70 males out of 120 applicants, there must be 50 females. For the minimum number of males to have a driver’s license all 50 females must have a driver’s license. Thus, the number of males having a driver’s license, will be 80 – 50 = 30. The maximum possible number of males having a driver’s license is 70. The ratio between the minimum and the maximum is 30 : 70 or 3 : 7.
Incorrect
Answer : c
Since, there are 70 males out of 120 applicants, there must be 50 females. For the minimum number of males to have a driver’s license all 50 females must have a driver’s license. Thus, the number of males having a driver’s license, will be 80 – 50 = 30. The maximum possible number of males having a driver’s license is 70. The ratio between the minimum and the maximum is 30 : 70 or 3 : 7.
