Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
Quiz-summary
0 of 5 questions completed
Questions:
- 1
- 2
- 3
- 4
- 5
Information
Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 5 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
- Not categorized 0%
- 1
- 2
- 3
- 4
- 5
- Answered
- Review
-
Question 1 of 5
1. Question
3yr ago, the average age of a family of 5 members was 17 yr. Even after the birth of a child, the average is same today. Find out the age of child.
Correct
Answer : d
Before 3 years
Total age of 5 members of a family = 17*5
= 85 years.
Present age of all family members = 85 + 3* 5
= 85 + 15
= 100 yr.
Average is same after child birth
So let the age of the child = x year
New total family member will be = 6
Average = sum/total
17 = x+100/6
17* 6 = x + 100
X = 102 – 100
X = 2 year.
Incorrect
Answer : d
Before 3 years
Total age of 5 members of a family = 17*5
= 85 years.
Present age of all family members = 85 + 3* 5
= 85 + 15
= 100 yr.
Average is same after child birth
So let the age of the child = x year
New total family member will be = 6
Average = sum/total
17 = x+100/6
17* 6 = x + 100
X = 102 – 100
X = 2 year.
-
Question 2 of 5
2. Question
The average age of three boys is 15yr. If the ratio of their ages is 3:5:7, what is the age of the oldest boy?
Correct
Answer : d
Average age of three boys = 15 years
Average = sum/ total
15 = sum/3
Sum of three boys = 15 *3
= 45 years.
Now the ratios are 3:5:7
So let the age of 1st person be = 3x
2nd person be = 5x
3rd person be = 7x
So sum will be –
3x + 5x +7x = 15x
Now as we know that sum is = 45 years.
So now both sum will be equal.
15x = 45
X = 45/15 = 3
X = 3 years
Respective ages will be = 3 * 3 = 9 years
2nd = 3 *5 = 15 years
3rd = 3 * 7 = 21 years
Incorrect
Answer : d
Average age of three boys = 15 years
Average = sum/ total
15 = sum/3
Sum of three boys = 15 *3
= 45 years.
Now the ratios are 3:5:7
So let the age of 1st person be = 3x
2nd person be = 5x
3rd person be = 7x
So sum will be –
3x + 5x +7x = 15x
Now as we know that sum is = 45 years.
So now both sum will be equal.
15x = 45
X = 45/15 = 3
X = 3 years
Respective ages will be = 3 * 3 = 9 years
2nd = 3 *5 = 15 years
3rd = 3 * 7 = 21 years
-
Question 3 of 5
3. Question
5 yr ago, the average age of Rashmi and Surbhi was 20 yr. Now, the average age of Rashmi ,Meeta and Surbhi is 30yr. What will be the age of Meeta after 15yr?
Correct
Answer : b
5 year ago, the sum of Rashmi and Surabhi’s
Age will be : 20 *2
= 40 years
Now present age of Rashmi, Surabhi will be = 40 +5* 5
= 50 year
Now Average age of Rashmi, Surabhji & Meeta = 30 years ( given )
So sum of Rashmi . Surabhi , & Meeta = 30 * 3
= 90 years.
So age of Meeta will be = 90 – 50 =40 years
After 15 years age of Meeta will be = 40 + 15
= 55 years
Incorrect
Answer : b
5 year ago, the sum of Rashmi and Surabhi’s
Age will be : 20 *2
= 40 years
Now present age of Rashmi, Surabhi will be = 40 +5* 5
= 50 year
Now Average age of Rashmi, Surabhji & Meeta = 30 years ( given )
So sum of Rashmi . Surabhi , & Meeta = 30 * 3
= 90 years.
So age of Meeta will be = 90 – 50 =40 years
After 15 years age of Meeta will be = 40 + 15
= 55 years
-
Question 4 of 5
4. Question
The average weight of 60 students in a class was calculated to be 40 kg. Later, it was found out that the weight of one of the students was calculated as 36 kg, whereas his actual weight was 33kg. What is the actual average weight of the students in the class ?
Correct
Answer : b
Average = sum/total no of observation
Average weight of 60 students = 40 kg
40 = sum/60
So sum of 60 students will be = 40 * 60
= 2400
But here 36kg is calculated and there should be 33kg.
So Now New sum = 2400 – 36 + 33
= 2400 – 3
= 2397 kg
So Required average weight = 2397/60
= 39.95 kg.
Incorrect
Answer : b
Average = sum/total no of observation
Average weight of 60 students = 40 kg
40 = sum/60
So sum of 60 students will be = 40 * 60
= 2400
But here 36kg is calculated and there should be 33kg.
So Now New sum = 2400 – 36 + 33
= 2400 – 3
= 2397 kg
So Required average weight = 2397/60
= 39.95 kg.
-
Question 5 of 5
5. Question
A person bought some oranges worth Rs.36 from each of the five markets at Rs. 1, Rs. 1.50, Rs. 1.80, Rs. 2 and Rs. 2.25 per orange, respectively. What is the average price of an orange ?
Correct
Answer : c
No of oranges bought by the person =36/1 +36/1.5 +36/1.8 +36/2 +36/2.25
= 36 + 24 + 20 + 18 + 16
= 114
Total Expenditure = 36 *5 = 180 Rs.
Thus. Average price of each orange = 180/114 = 1.58 Rs
Incorrect
Answer : c
No of oranges bought by the person =36/1 +36/1.5 +36/1.8 +36/2 +36/2.25
= 36 + 24 + 20 + 18 + 16
= 114
Total Expenditure = 36 *5 = 180 Rs.
Thus. Average price of each orange = 180/114 = 1.58 Rs
