Insta–DART (Daily Aptitude and Reasoning Test) 18 November 2020
Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too. We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The average of the test scores of a class of ‘m’ students is 70 and that of ‘n’ students is 91. When the scores of both the classes are combined, the average is 80. What is n/m?
Correct
Answer : d
According to the question,
70m + 91n = 80 (m+n)
70m+91n = 80m +80n
10m = 11n
n/m = 10/11
Incorrect
Answer : d
According to the question,
70m + 91n = 80 (m+n)
70m+91n = 80m +80n
10m = 11n
n/m = 10/11
Question 2 of 5
2. Question
If 47a + 47b = 5452, what is the average of a and b?
Correct
Answer : d
47 ( a + b ) = 5452
a + b = (5452/47) = 116
So Average value = (a+b)/2 = (116/2) = 58
Incorrect
Answer : d
47 ( a + b ) = 5452
a + b = (5452/47) = 116
So Average value = (a+b)/2 = (116/2) = 58
Question 3 of 5
3. Question
The average salary per head of all workers of an institution is Rs. 60. The average salary per head of 12 officers is Rs. 400. The average salary per head of the rest is Rs. 56. Then, the total number of workers in the institution is
Correct
Answer :b
Let the total number of workers = x
According to the question
60x = 12 × 400 + 56 ( x – 12 )
60x – 56x = 4800 – 672
4x = 4128
X = 1032
Incorrect
Answer :b
Let the total number of workers = x
According to the question
60x = 12 × 400 + 56 ( x – 12 )
60x – 56x = 4800 – 672
4x = 4128
X = 1032
Question 4 of 5
4. Question
A car travels a certain distance from town A to B at the speed of 42 Km/h and from town B to town A at a speed of 48 Km/h. What is the average speed of the car ?
Correct
Answer : d
If two equal distances are covered at different speed at A km/h and B km/h respectively, then Average speed during the whole journey
= (2AB)/(A+B) km/h
So Average speed of the car = ( 2* 42*48)/(42+48)= (2*42*48)/90
= 44.8 km/h.
Incorrect
Answer : d
If two equal distances are covered at different speed at A km/h and B km/h respectively, then Average speed during the whole journey
= (2AB)/(A+B) km/h
So Average speed of the car = ( 2* 42*48)/(42+48)= (2*42*48)/90
= 44.8 km/h.
Question 5 of 5
5. Question
A man divides his total route of journey into three equal parts and decides to travel the three parts with speed of 15 km/h, 10km/h and 5km/h, respectively. Find his average speed of during journey.
Correct
Answer :d
We now that, if three equal distances are covered at different speeds of A, B and C km/h respectively, then average speed during whole journey
= (3ABC)/[(AB+BC+CA)] km/h
So Required average speed = (3*15*10*5)/[(15*10)+(10*5)+(15*5)]
= 8.18 km/h
Incorrect
Answer :d
We now that, if three equal distances are covered at different speeds of A, B and C km/h respectively, then average speed during whole journey
= (3ABC)/[(AB+BC+CA)] km/h
So Required average speed = (3*15*10*5)/[(15*10)+(10*5)+(15*5)]
= 8.18 km/h
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