Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Mangoes trees, 42 apples trees and 56 oranges trees have to be planted in rows such that each row contains the same number of trees one variety only. Minimum number of rows in which the above trees may be planted is ?
Correct
Solution: b
H.C.F. of 21, 42, 56 = 7
Number of rows of mango trees, apple trees and oranges trees are 21/7 = 3, 42/7 = 6 and 56/7 = 8
∴ Required number of rows = (3 + 6 + 8 ) = 17Incorrect
Solution: b
H.C.F. of 21, 42, 56 = 7
Number of rows of mango trees, apple trees and oranges trees are 21/7 = 3, 42/7 = 6 and 56/7 = 8
∴ Required number of rows = (3 + 6 + 8 ) = 17 -
Question 2 of 5
2. Question
Three pieces of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length, What is the greatest possible length of each plank ?
Correct
Solution: a
Greatest possible length of each plank = H.C.F of 42, 49, 63 = 7 m
Incorrect
Solution: a
Greatest possible length of each plank = H.C.F of 42, 49, 63 = 7 m
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Question 3 of 5
3. Question
The largest natural number, which exactly divides the products of any four consecutive natural numbers, is ?
Correct
Solution: c
In any 4 consecutive natural numbers:
Two numbers will be divisible by 2, one of which will be divisible by 4, at least one number will be divisible by 3.
These facts give us a lower bound of 2 x 4 x 3 = 24 for the solution.
But 24 is also the product of the first 4 consecutive natural numbers, so it is also an upper bound.
Incorrect
Solution: c
In any 4 consecutive natural numbers:
Two numbers will be divisible by 2, one of which will be divisible by 4, at least one number will be divisible by 3.
These facts give us a lower bound of 2 x 4 x 3 = 24 for the solution.
But 24 is also the product of the first 4 consecutive natural numbers, so it is also an upper bound.
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Question 4 of 5
4. Question
The total number of prime factors of the products (8)20, (15)24, (7)15 is ?
Correct
Solution: c
Since 2, 3, 5, 17 are prime numbers and
The given expression = (23)20 x (3 x 5)24 x (17)15
= 260 x 324 x 524 x 1715So the total number of prime factors in the given expression is (60 + 24 + 24 + 15 ) = 123
Incorrect
Solution: c
Since 2, 3, 5, 17 are prime numbers and
The given expression = (23)20 x (3 x 5)24 x (17)15
= 260 x 324 x 524 x 1715So the total number of prime factors in the given expression is (60 + 24 + 24 + 15 ) = 123
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Question 5 of 5
5. Question
The traffic lights at three different road crossings changes after every 48 sec., 72 sec. and 108 sec. respectively. If they all change simultaneously at 8 : 20 : 00 hrs, then they will again change simultaneously at?
Correct
Solution: a
Interval of changes = (L . C . M of 48, 72, 108) sec. = 432 sec.
So, the lights will simultaneously changes after every 432 seconds i,e 7 min. 12 sec.
So, the next simultaneously changes will take place at 8 : 27 : 12 hrs.Incorrect
Solution: a
Interval of changes = (L . C . M of 48, 72, 108) sec. = 432 sec.
So, the lights will simultaneously changes after every 432 seconds i,e 7 min. 12 sec.
So, the next simultaneously changes will take place at 8 : 27 : 12 hrs.
