Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Find all the factors of 120
Correct
Answer : d
120 = 2 * 2 * 2 * 3 * 5
= 23*31*51
Factors = ( 3 + 1 ) ( 1 + 1 ) ( 1 + 1 ) =16
Incorrect
Answer : d
120 = 2 * 2 * 2 * 3 * 5
= 23*31*51
Factors = ( 3 + 1 ) ( 1 + 1 ) ( 1 + 1 ) =16
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Question 2 of 5
2. Question
Number of zeros at the end of
Correct
Answer : c
Incorrect
Answer : c
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Question 3 of 5
3. Question
Find unit digit of 1111+1212+1313+1414+1515
Correct
Answer : a
Unit digit of 1111is = 1
Unit digit of 1212 is = 6
Unit digit of 1313 is = 3
Unit digit of 1414 is = 6
Unit digit of 1515 is = 5
So Unit digit of given sum will be = 1 + 6 + 3 + 6 + 5
= 21
i.e = 1
Incorrect
Answer : a
Unit digit of 1111is = 1
Unit digit of 1212 is = 6
Unit digit of 1313 is = 3
Unit digit of 1414 is = 6
Unit digit of 1515 is = 5
So Unit digit of given sum will be = 1 + 6 + 3 + 6 + 5
= 21
i.e = 1
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Question 4 of 5
4. Question
Find the Number of divisions of 1420
Correct
Answer : d
1420 = 142 * 10 = 71 * 2 * 2 * 5 = 22*51*711
Number of divisor = ( 2 + 1 ) ( 1 + 1 ) (1 + 1 )
= 12
Number of divisors is Nothing but the Number of factors of 1420.
Incorrect
Answer : d
1420 = 142 * 10 = 71 * 2 * 2 * 5 = 22*51*711
Number of divisor = ( 2 + 1 ) ( 1 + 1 ) (1 + 1 )
= 12
Number of divisors is Nothing but the Number of factors of 1420.
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Question 5 of 5
5. Question
The LCM of ( 16 – and ( + x – 6 ) is
Correct
Answer : d
16 – x2 = ( 4 – x ) ( 4 + x )
(x2+x-6)=(x+3)(x-3)
LCM will be = ( 16 – x2 ) ( x2+ x – 6 )
Incorrect
Answer : d
16 – x2 = ( 4 – x ) ( 4 + x )
(x2+x-6)=(x+3)(x-3)
LCM will be = ( 16 – x2 ) ( x2+ x – 6 )
