Insta–DART (Daily Aptitude and Reasoning Test) 2020 - 21
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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP-2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
The LCM of two numbers is 48 .The numbers are in the ratio of 2:3. Find the sum of the numbers
Correct
Solution: Option (c)
Let numbers be 2x & 3x
According to question, 6x=48 (LCM = 6)
x = 8
Required sum = 2x + 3x = 5x
Now x = 8
Sum = 5 x 8 = 40
Incorrect
Solution: Option (c)
Let numbers be 2x & 3x
According to question, 6x=48 (LCM = 6)
x = 8
Required sum = 2x + 3x = 5x
Now x = 8
Sum = 5 x 8 = 40
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Question 2 of 5
2. Question
The product of two whole numbers is 1500 and their HCF is 10. Find the LCM.
Correct
Solution: Option (b)
Product of two numbers = 1500
HCF = 10
According to formula,
Product of two numbers = HCF x LCM
1500 = 10 x LCM
LCM = 1500/10 = 150
Incorrect
Solution: Option (b)
Product of two numbers = 1500
HCF = 10
According to formula,
Product of two numbers = HCF x LCM
1500 = 10 x LCM
LCM = 1500/10 = 150
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Question 3 of 5
3. Question
Find the greatest numbers of 3-digits which when divided by 6,9,12 leaves 3 as remainder in each case
Correct
Solution: Option (a)
Greatest number of three digits = 999
LCM of 6,9,12
1 1 1
Required LCM = 2x2x3x3 = 36
Now, 999/36 = 27
Remainder = 27
Required Number = 999-27+3 = 975
Incorrect
Solution: Option (a)
Greatest number of three digits = 999
LCM of 6,9,12
1 1 1
Required LCM = 2x2x3x3 = 36
Now, 999/36 = 27
Remainder = 27
Required Number = 999-27+3 = 975
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Question 4 of 5
4. Question
What will be the greatest number that divides 1023 and 750 leaving remainders 3 and 2, respectively
Correct
Solution: Option (a)
Incorrect
Solution: Option (a)
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Question 5 of 5
5. Question
The least number which should be added to 2497; so that the sum is exactly divisible by 5,6,4,3 is-
Correct
Solution: Option (c)
LCM of 5,6,4 & 3
LCM of 5,6,4,3 = 60
On dividing 2497 by 60
The remainder is 37,
Number to be added = 60 – 37 = 23
Incorrect
Solution: Option (c)
LCM of 5,6,4 & 3
LCM of 5,6,4,3 = 60
On dividing 2497 by 60
The remainder is 37,
Number to be added = 60 – 37 = 23
